输入的意外结束（在字符2处）

Question

``

我正在尝试使用getx状态管理从API获取数据

import 'dart:convert';
import 'package:e_sante/Data/User.dart';
import 'package:get/get.dart';
import 'package:http/http.dart' as http;

class Controller extends GetxController{
  var patientList=<Patient>[].obs;
  var isLoading = true.obs;
  @override
  void onInit(){
    super.onInit();
    fetchPatientData();
  }
  Future<void> fetchPatientData() async{
    final response= await http.get(Uri.parse('http://10.0.2.2:3000/patients?Ip=C123456'));
    if(response.statusCode==200){

      for(var i = 0; i < response.body.length; i++){
        Patient patient= Patient.fromJson(jsonDecode(response.body[i]));

        patientList.add(Patient(
            Ip: patient.Ip,
            Nom: patient.Nom,
            Age: patient.Age,
            Mail: patient.Mail,
            Tel: patient.Tel,
            Password: patient.Password),
        );

      }
      isLoading.value=true;

    }else{
      Get.snackbar('Error loading data!', 'Sever responded: ${response.statusCode}:${response.reasonPhrase.toString()}');
    }

  }
}

class Patient{
    final String Ip,Nom,Mail,Password;
   final int Age,Tel;
  Patient({
    required this.Ip,
    required this.Nom,
    required this.Age,
    required this.Mail,
    required this.Tel,
    required this.Password
  });
  factory Patient.fromJson(Map<String, dynamic> json){
    return Patient(
        Ip: json['Ip'],
        Nom: json['Nom'],
        Age: json['Age'],
        Mail: json['Mail'],
        Tel: json['Tel'],
        Password: json['Password']
    );
  }
}

import 'package:get/get.dart';

import 'Data/controller.dart';

class ControllerBindings extends Bindings{ @override void dependencies() { Get.put<Controller>(Controller()); } }

时，当我热加载我的应用程序时，我遇到了此错误（未经措辞的例外：类型'list＆lt; dynamic＆gt;'不是类型的子类型'map＆lt; string，dynamic＆gt ;'）并且当我打开屏幕时应显示数据时，屏幕继续加载

`

Answer 1

根据您的错误消息，看起来像是JSON对象的API返回列表，但您正在尝试将JSON对象的此列表映射到JSON对象。尝试将响应映射到JSON列表，然后可能会起作用。

List<Patient> patientsFromJson(String body) =>
    List<Patient>.from(jsonDecode(body).map((x) => Patient.fromJson(x)));

然后使用此患者映射API响应

Future<void> fetchPatientData() async{
    final response= await http.get(Uri.parse('http://10.0.2.2:3000/patients?Ip=C123456'));

    if(response.statusCode==200){
      var patients = patientsFromJson(response.body);

      for (var patient in patients) {
        patientList.add(patient);
      }

     // patientList.addAll(patients);
      isLoading.value=true;
    }else{
      Get.snackbar('Error loading data!', 'Sever responded: ${response.statusCode}:${response.reasonPhrase.toString()}');
    }
  }

Answer 2

1.算法误差分辨率
响应。Body是列表，但您可以添加到地图中，因此您可以更改此

for(var i = 0; i < response.body.length; i++){
     Patient patient= Patient.fromJson(jsonDecode(response.body[i]));
     patientList.add(Patient(
          Ip: patient.Ip,
          Nom: patient.Nom,
          Age: patient.Age,
          Mail: patient.Mail,
          Tel: patient.Tel,
          Password: patient.Password),
      );

}

2.当发生错误时，请注意将其停止加载
您必须捕获错误并停止加载，但是发生错误将来无法捕获。
因此，请尝试此

//somewhere 
fetchPatientData().then(processValue).catchError(handleError);

请参阅 https：// - 接受