创建多个类似的基因并使用其输出

发布于 2025-01-18 12:48:29 字数 774 浏览 1 评论 0原文

我有一个如下所示的正则。它基本上运行一个简单的 go 模板工具，获取资源名称、json 文件和模板并输出渲染的文件。我有一堆资源，所有这些资源都需要位于单独的文件中，并最终打包到一个容器中。

resources = ["foo", "bar"]
[genrule(
    name = "generate_" + resource + "_config",
    srcs = [
        "//some:tool:config.tmpl",
        "//some:json",
    ],
    outs = [resource + ".hcl"],
    cmd = "$(location //some/tool:template) -resource " + resource + " -json_path=$(location //some:json) -template=$(location //some/tool:config.tmpl) -out=$@",
    tools = [
        "/some/tool:template",
    ],
) for resource in resources]

上面将生成一些名为 generate_foo_config 和 generate_bar_config 的规则，并且文件输出正确。然而，如果不直接在文件组或 pkg_tar 规则中指定而不枚举每一项，我无法弄清楚如何使用每一项。我希望能够向 resources 变量添加新内容，并将其自动包含在文件组或 tar 中，以便稍后在构建规则中使用。这可能吗？

原文

I have a genrule that looks like the below. It basically runs a simple go template tool that gets a resource name, a json file and template and outputs the rendered file. I have a bunch of resources that all need to be in separate files and ultimately packaged into a container.

resources = ["foo", "bar"]
[genrule(
    name = "generate_" + resource + "_config",
    srcs = [
        "//some:tool:config.tmpl",
        "//some:json",
    ],
    outs = [resource + ".hcl"],
    cmd = "$(location //some/tool:template) -resource " + resource + " -json_path=$(location //some:json) -template=$(location //some/tool:config.tmpl) -out=$@",
    tools = [
        "/some/tool:template",
    ],
) for resource in resources]

The above will generate a few rules named generate_foo_config and generate_bar_config and the files output correctly. I however cannot figure out how to use each one without specifying them directly in a filegroup or pkg_tar rule without enumerating each one. I would like to be able to add a new thing to the resources variable, and have it automatically included in the filegroup or tar for use in a build rule later. Is this possible?

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因为看清所以看轻 2025-01-25 12:48:29

使用列表理解，就像您已经创建了属规则。像这样：

pkg_tar(
    name = "all_resources",
    srcs = [":generate_" + resource + "_config" for resource in resources],
)

您还可以将列表放入 BUILD 文件中的变量中以多次使用它：

all_resources = [":generate_" + resource + "_config" for resource in resources]
pkg_tar(
    name = "all_resources",
    srcs = all_resources,
)
filegroup(
    name = "resources_filegroup",
    srcs = all_resources,
)

Use a list comprehension, like you've got creating the genrules. Something like this:

pkg_tar(
    name = "all_resources",
    srcs = [":generate_" + resource + "_config" for resource in resources],
)

You can also put the list in a variable in the BUILD file to use it multiple times:

all_resources = [":generate_" + resource + "_config" for resource in resources]
pkg_tar(
    name = "all_resources",
    srcs = all_resources,
)
filegroup(
    name = "resources_filegroup",
    srcs = all_resources,
)

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