C计划调试：无法使Makefile与GDB一起工作
我有一个makefile，如下所示：
CC=gcc
CFLAGS=-g -Wall -Wextra
PTHREADS=-lpthread
all: client.o threadpool.o
$(CC) $(CFLAGS) -o example client.o threadpoool.o $(PTHREADS)
client.o: client .c
$(CC) $(CFLAGS) -c client.c $(PTHREADS)
threadpool.o: threadpool.c threadpool.h
$(CC) $(CFLAGS) -c client.c $(PTHREADS)
clean:
rm -rf *.o
rm -rf example
但是，当我运行makefile然后尝试将示例加载到GDB中时：
$ make
$ gdb ./example
... ...没有发现调试符号。谁能帮我理解这一点？这是我第一次尝试使用GDB，并且通常是C编程的新手。谢谢。
我尝试添加-g和-wextra标志，但这无效。
I have a makefile as follows:
CC=gcc
CFLAGS=-g -Wall -Wextra
PTHREADS=-lpthread
all: client.o threadpool.o
$(CC) $(CFLAGS) -o example client.o threadpoool.o $(PTHREADS)
client.o: client .c
$(CC) $(CFLAGS) -c client.c $(PTHREADS)
threadpool.o: threadpool.c threadpool.h
$(CC) $(CFLAGS) -c client.c $(PTHREADS)
clean:
rm -rf *.o
rm -rf example
However, when I run the makefile and then try and load example into GDB like so:
$ make
$ gdb ./example
...it says no debugging symbols found. Can anyone help me understand this? It is my first time attempting to use GDB and am very new to C programming in general. Thank you.
I tried to add the -g and -Wextra flags but this did not work.
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运行 make clean，然后重新运行 make 并将其加载到 gdb 中即可。
Running make clean and then re running make and loading it into gdb worked.