rl_replace_line 函数无效

Question

我正在尝试运行此代码，但此功能仍然有问题：

# include <unistd.h>
# include <stdio.h>
# include <stdlib.h>
# include <string.h>
# include <limits.h>
# include <errno.h>
# include <readline/readline.h>
# include <readline/history.h>
# include <signal.h>

void sig_handler()
{
    printf ("\n");
    rl_on_new_line();
    rl_replace_line("", 0);
    rl_redisplay();
}
int main()
{
    signal(SIGQUIT, SIG_IGN);
    signal(SIGINT, sig_handler);
    while (1)
    {
        str = readline(BBLU"shell$ "BYEL);
    }
} 

我尝试使用Hombrew安装ReadLine-8.0 当我这样做时：

gcc -Wall -Werror -Wextra -lreadline ./readline-8.0/shlib/libreadline.8.0.dylib main.c

我仍然无法编译该程序。

我尝试做

gcc -wall -werror -werror -wextra main.c -lreadline -l ./readline-8.0/shlib -l ./readline-8.0/

and

gcc -wall -wall -werror-werror- wextra -lreadline -l ./readline-8.0/shlib -l ./readline-8.0/ main.c没有区别。

这是结果：

main.c：50：2：错误：函数'rl_replace_line'的隐式声明在c99 [-werror，-wimplicer-function-unction-declaration] rl_replace_laration] rl_replace_line（“”，0）; ^生成1个错误。