如何格式化数字以具有n个整数和小数位？

发布于 2025-01-18 03:11:03 字数 372 浏览 0 评论 0原文

假设我有一个浮点数 x，它有一个整数部分 a 和小数部分 b，即 x = ab。如何在 JavaScript 中格式化 x 使其最多包含 n 位数字，如下所示：

const n = 5
format(123.0) == '123'
format(123.01) == '123.01'
format(123.012) == '123.01'
format(0.0123) == '0.0123'
format(0.01234) == '0.0123'

原文

Say I have a float x that has a whole part a and decimal part b i.e. x = a.b. How can I format x in JavaScript such that it'll have at most n digits, as shown below:

const n = 5
format(123.0) == '123'
format(123.01) == '123.01'
format(123.012) == '123.01'
format(0.0123) == '0.0123'
format(0.01234) == '0.0123'

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兔姬 2025-01-25 03:11:03

基于最近删除的具有逻辑但实际上不起作用的答案，我想出了这个解决方案：

const format = (number, digits = 5) => {

  const str = number + ''; // convert to string
  let [integer, decimal] = str.split('.'); // split by dot delimiter

  const integerDigits = integer.length;

  if (integerDigits >= digits) {
    return integer;
  } else {
    let decimalDigits = digits - integerDigits;
    decimal = Number('0.' + decimal.substring(0, decimalDigits)).toString();
    return integer + '.' + decimal.split('.')[1];
  }
}

Based on a recently deleted answer that had the logic but didn't really work, I came up with this solution:

const format = (number, digits = 5) => {

  const str = number + ''; // convert to string
  let [integer, decimal] = str.split('.'); // split by dot delimiter

  const integerDigits = integer.length;

  if (integerDigits >= digits) {
    return integer;
  } else {
    let decimalDigits = digits - integerDigits;
    decimal = Number('0.' + decimal.substring(0, decimalDigits)).toString();
    return integer + '.' + decimal.split('.')[1];
  }
}

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