如何在Python中并行计数2列表？

发布于 2025-01-17 23:47:24 字数 393 浏览 1 评论 0原文

我有两个列表。

Numbers = ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10']
Letters = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j']

我想并行计算这两个列表。当在一个列表中选择下一个值时，也会在另一个列表中选择下一个值。

这样：

Number: 1, Letter: a
Number: 2, Letter: b
Number: 3, Letter: c
Number: 4, Letter: d
Number: 5, Letter: e
Number: 6, Letter: f

等等。我该怎么做？

原文

I have two lists.

Numbers = ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10']
Letters = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j']

I want to count these two lists in parallel. When the next value is selected in one list, the next value is selected in another list too.

Like this:

Number: 1, Letter: a
Number: 2, Letter: b
Number: 3, Letter: c
Number: 4, Letter: d
Number: 5, Letter: e
Number: 6, Letter: f

and so on.
How can I do this?

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メ斷腸人バ 2025-01-24 23:47:25

i = 0
while i <len(Numbers):
    print(Numbers[i], Letters[i])
    i+=1

i = 0
while i <len(Numbers):
    print(Numbers[i], Letters[i])
    i+=1

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烈酒灼喉 2025-01-24 23:47:24

Pythonic Way

for x,y in  zip(Numbers,Letters ):
    print(f"Number{x},Letter{y}")

Pythonic way

for x,y in  zip(Numbers,Letters ):
    print(f"Number{x},Letter{y}")

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小女人ら 2025-01-24 23:47:24

for i in range(len(Numbers)):
    print("Number: " + Numbers[i] + ", Letter: " + Letters[i])

输出：

Number: 1, Letter: a
Number: 2, Letter: b
Number: 3, Letter: c
Number: 4, Letter: d
Number: 5, Letter: e
Number: 6, Letter: f
Number: 7, Letter: g
Number: 8, Letter: h
Number: 9, Letter: i
Number: 10, Letter: j

for i in range(len(Numbers)):
    print("Number: " + Numbers[i] + ", Letter: " + Letters[i])

Outputs:

Number: 1, Letter: a
Number: 2, Letter: b
Number: 3, Letter: c
Number: 4, Letter: d
Number: 5, Letter: e
Number: 6, Letter: f
Number: 7, Letter: g
Number: 8, Letter: h
Number: 9, Letter: i
Number: 10, Letter: j

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