如何迭代字符串列表并在 dbo 上调用它们？

发布于 2025-01-17 23:04:23 字数 526 浏览 0 评论 0原文

我是一个学生，很抱歉，这真的很愚蠢。我有一个名为“人”的模型。人们拥有大量属性，例如身高重量，眼颜料等。我可以使用

（typeof（person）.getProperties（）select t.name）

获得人的属性列表。然后，我需要将所有人员对象插入2D数组中，有一种方法与循环双重循环我可以使用列表访问DBO，而不是将每个属性称为硬码？

我在想像

foreach (var (item, i) in properties.Select((item, i ) => (item, i)))
{
    array[0][i] = properties[i];
    foreach (var(person, j) in people.Select((person, j)=>(person, j)))
    {
    //this is the part I'm struggling with
    array[j][i] = People.property[i];//???
    }
}

原文

I'm a student so sorry if this is really stupid. I have a model called Person which is IEnumerable. Person holds a large amount of attributes such as height weight, eyecolor etc. I can get the properties of Person using

(from t in typeof(Person).GetProperties() select t.Name)

which results in a list. I need to then insert all the Person objects into a 2d array is there a way with a double for loop I can use the list to access the dbo instead of calling every property as hard code?

I was thinking something like

foreach (var (item, i) in properties.Select((item, i ) => (item, i)))
{
    array[0][i] = properties[i];
    foreach (var(person, j) in people.Select((person, j)=>(person, j)))
    {
    //this is the part I'm struggling with
    array[j][i] = People.property[i];//???
    }
}

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紙鸢 2025-01-24 23:04:23

简单的答案是捕获属性本身（而不仅仅是其名称），然后使用 .GetValue() 方法从每个人处获取属性的值。

var properties = typeof(Person).GetProperties();
...
    array[j][i] = item.GetValue(person);

但乔尔在他的评论中提出了一个很好的观点。我会质疑您需要一个二维数组结构来保存每个人的所有值的假设。仔细看看你实际上想要解决的问题，因为可能有更好的方法来解决它。

The simple answer is to capture the property itself (not just its name), and then use the .GetValue() method to get the property's value from each person.

var properties = typeof(Person).GetProperties();
...
    array[j][i] = item.GetValue(person);

But Joel makes a good point in his comment. I would challenge the assumption that you need a 2d array structure to hold all the values for each Person. Take a good look at the problem you're actually trying to solve, because there's probably a better way to solve it.

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