如何从散点图中排除x = 0或y = 0值？
我有一个看起来像这样的散点图：
我正在尝试制作它，以便如果x = 0或y = 0，那么散布点就被忽略了，只有x和y的值 等于零：
既大于或 net/lohuv.png“ alt =”在此处输入图像描述>
这是我到目前为止尝试的：
x = df['tp']
y = df['tp1']
x = x[x > 0.0]
y = y[y > 0.0]
plt.scatter(x,y)
我对此遇到以下内容：
ValueError: x and y must be the same size
有理由是有理由我可以使用的另一种解决方案？
I have a scatter graph that looks like this:
I'm trying to make it so that if x=0 or y=0 then that scatter point is ignored, and only the values where x and y are both greater than or equal to zero are taken:
Here's what I've tried so far:
x = df['tp']
y = df['tp1']
x = x[x > 0.0]
y = y[y > 0.0]
plt.scatter(x,y)
To which I get met with the following:
ValueError: x and y must be the same size
Is there a reason for why this isn't working, or a different solution that I could use?
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过滤时，您正在更改过滤器的上下文，但是可以做：
You are changing the context of the filter while filtering, but you can do:
问题是您需要将同时排除
xs和ys，其中一个是0。想象一下，
x和y中的5中有10， 0 s。您的X和y大小不会相同。更重要的是，您将有错误的对X和ys。你需要什么？
查找
x和y拒绝蒙版，然后将它们应用于xanys：：The problem is you need to exclude both
xs andys where either one is0.Imagine you have 10,
0s inxand 5 iny. Yourxandysize would not be the same. And more importantly you'll have wrong pairs ofxandys.What you need?
find
xandyrejection masks then apply them to bothxanys:此链接中已经给出了类似的答案。我希望它能帮助你。
不在 matplotlib 中绘制“零”或更改零为无 [Python]
A similar answer is already given in this link. I hope it will help you out.
Not plotting 'zero' in matplotlib or change zero to None [Python]