Mongoose Schema：为模式分配 Typescript 接口

Question

我想使用接口键入杂种模式。这样：

const mongoose = require('mongoose')
const { Schema, Model, Document } = mongoose;

interface WordInterface extends Document {
    _id: string | null;
    wordType: WordTypes;
    text: string;
    verses: VerseFromTo[] | null;
    createdAt: number;
    modifiedAt: number;
    creator: string;
}

const wordSchema = new Schema({
    _id: { type: String },
    wordType: { type: Object as () => WordTypes, required: true },
    text: { type: String, required: true },
    verses: { type: Object as () => VerseFromTo[] },
    createdAt: { type: Number, required: true },
    modifiedAt: { type: Number, required: true },
    creator: { type: String, required: true }
});

const words: typeof Model<WordInterface> = mongoose.model('words', wordSchema);

但是在这条线中，我会遇到一个错误：

const emotions: typeof Model<WordInterface> = mongoose.model('emotions', emotionSchema);
                            ^               ^

上面的行下方的上箭头显示了两个绒毛错误。我是打字稿的菜鸟，所以我可能会误解该语法。错误都是： ts1005：'，'预期。

我无法弄清楚我做错了什么。我尝试了这些文档中的示例：

• https://mongoosejs.coms.com/docs/docs/dypescript.html
• https://thecodebarrain.com/working-with-with-with-with-with-with-mongoose-ingoose-in-typescript。 html

我也尝试输入模式，但它行不通：

const wordSchema = new Schema<WordInterface>({

但是它给出了以下错误：

TS2347: Untyped function calls may not accept type arguments.

卡住！非常感谢;）

  "dependencies": {
    "@types/body-parser": "^1.19.0",
    "body-parser": "^1.19.0",
    "dotenv": "^8.2.0",
    "express": "^4.17.1",
    "mongoose": "^5.10.7"
  },
  "devDependencies": {
    "@types/express": "^4.17.8",
    "@typescript-eslint/eslint-plugin": "^5.16.0",
    "@typescript-eslint/parser": "^5.16.0",
    "eslint": "^8.12.0",
    "nodemon": "^2.0.4",
    "ts-node": "^9.0.0",
    "typescript": "^4.0.3",
    "webpack": "^4.44.2",
    "webpack-cli": "^3.3.12"
  }