每个月底前的天数

发布于 2025-01-17 21:11:15 字数 317 浏览 0 评论 0原文

如何获得“ 2018/01/29'，''2018/02/26'，哪个是在每个月末之前的第二天，例如从下面的python的日报？

daylist=['2018/01/25','2018/01/26','2018/01/29','2018/01/30','2018/01/31','2018/02/01','2018/02/20','2018/02/23','2018/02/26','2018/02/27','2018/02/28','2018/03/02']

（每秒钟都可以通过日间[-2 :: -2]获得，但我不知道如何在每个月的每个月之前获得第二天）

原文

How to get '2018/01/29', '2018/02/26' which are second days before every end of month, such as from the daylist below in Python?

daylist=['2018/01/25','2018/01/26','2018/01/29','2018/01/30','2018/01/31','2018/02/01','2018/02/20','2018/02/23','2018/02/26','2018/02/27','2018/02/28','2018/03/02']

(Every secondays can be obtained by daylist[-2::-2], but I have no idea how to get second days before every end of the month)

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秋凉 2025-01-24 21:11:15

您可以通过检查日期是否是一个月结束，然后减去两天的日期来完成此操作。前任：

from datetime import datetime, timedelta

daylist=['2018/01/25','2018/01/26','2018/01/29','2018/01/30','2018/01/31','2018/02/01','2018/02/20','2018/02/23','2018/02/26','2018/02/27','2018/02/28','2018/03/02']

# parse to datetime first
dt_list = [datetime.strptime(d, "%Y/%m/%d") for d in daylist]

# now shift each date by one day and see if the month changes - if so,
# you have a month end...
two_days_before_end = []
for dt in dt_list:
    # assumes the dt_list is sorted:
    if (dt + timedelta(days=1)).month != dt.month:
        two_days_before_end.append(dt-timedelta(days=2))

print(two_days_before_end)
# [datetime.datetime(2018, 1, 29, 0, 0), datetime.datetime(2018, 2, 26, 0, 0)]

You could do that by checking if a date is the end of a month, then subtracting two days to get the date two days before that. Ex:

from datetime import datetime, timedelta

daylist=['2018/01/25','2018/01/26','2018/01/29','2018/01/30','2018/01/31','2018/02/01','2018/02/20','2018/02/23','2018/02/26','2018/02/27','2018/02/28','2018/03/02']

# parse to datetime first
dt_list = [datetime.strptime(d, "%Y/%m/%d") for d in daylist]

# now shift each date by one day and see if the month changes - if so,
# you have a month end...
two_days_before_end = []
for dt in dt_list:
    # assumes the dt_list is sorted:
    if (dt + timedelta(days=1)).month != dt.month:
        two_days_before_end.append(dt-timedelta(days=2))

print(two_days_before_end)
# [datetime.datetime(2018, 1, 29, 0, 0), datetime.datetime(2018, 2, 26, 0, 0)]

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