同时创建子类和对象

发布于 2025-01-17 18:07:25 字数 402 浏览 1 评论 0原文

我正在寻找与 Java 习惯用法等效的 C# 语言。

在Java中，如果你有一个抽象类，你不能直接创建该类的对象；您需要首先对其进行子类化（并提供抽象方法的重写）。但实际上您可以同时创建子类和对象：

public abstract class Type {
  abstract Kind kind();
  public static final Type BOOLEAN =
      new Type() {
        @Override
        Kind kind() {
          return Kind.BOOLEAN;
        }
      };

上面的内容并未逐字翻译为 C#；有等效的习语吗？或者您只需要手写出来，首先声明一个命名子类，然后创建该子类的对象？

原文

I am looking for a C# equivalent of a Java idiom.

In Java, if you have an abstract class, you cannot directly create an object of that class; you need to subclass it (and provide an override of the abstract methods) first. But you can actually create the subclass and object at the same time:

public abstract class Type {
  abstract Kind kind();
  public static final Type BOOLEAN =
      new Type() {
        @Override
        Kind kind() {
          return Kind.BOOLEAN;
        }
      };

The above doesn't translate verbatim into C#; is there an equivalent idiom? Or do you just need to write it out longhand, declaring a named subclass first, then creating an object of the subclass?

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撩发小公举 2025-01-24 18:07:25

不幸的是没有。也许您可以尝试创建一个实现您的类 Type 的私有类，然后创建一个返回该类的方法？

但是，也许看看您想要实现的内容。这可能不适合您的问题。

public abstract class Type
{
    public abstract string Kind();

    public static Type BOOLEAN()
    {
        return new BooleanType();
    }

    private class BooleanType : Type
    {
        public override string Kind()
        {
            return "Boolean";
        }
    }
}

Unfortunately not. Maybe you can try making a private class which implements your class Type and then make a method that returns that?

However, maybe take a look at what you're trying to implement. This might not be the right pattern for your problem.

public abstract class Type
{
    public abstract string Kind();

    public static Type BOOLEAN()
    {
        return new BooleanType();
    }

    private class BooleanType : Type
    {
        public override string Kind()
        {
            return "Boolean";
        }
    }
}

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