python：从嵌套列表中删除时保留某些值

Question

我有一个嵌套列表，如下所示：

my_list = [['id_1', {'frame':[{'door': 'window', 'closet':'pinches'}], 'utterance':'sentence number 1', 'speaker':'silver'}],
 ['id_2',{'frame':[{'door': 'window', 'closet':'pinches'},{'door': 'new_door', 'closet':'hinges'}], 'utterance':'sentence number 2', 'speaker':'silver'}],
 ['id_3', {'frame':[{'door': 'window', 'closet':'pins'}], 'utterance':'sentence number 3', 'speaker':'gold'}]]

如果列表包含值“gold”，我想从 my_list 中删除该列表，因此我执行了以下操作。

removed =[i for i in [item[1] for item in my_list] if not(i['speaker'] == 'gold')]

print(removed) 
#output: [{'frame': [{'door': 'window', 'closet': 'pinches'}], 'utterance': 'sentence number 1', 'speaker': 'silver'}, {'frame': [{'door': 'window', 'closet': 'pinches'}, {'door': 'new_door', 'closet': 'hinges'}], 'utterance': 'sentence number 2', 'speaker': 'silver'}]

但我想保留“id_number”，所以我想要的输出是：

my_new_list = [['id_1', {'frame':[{'door': 'window', 'closet':'pinches'}], 'utterance':'sentence number 1', 'speaker':'silver'}],
 ['id_2',{'frame':[{'door': 'window', 'closet':'pinches'},{'door': 'new_door', 'closet':'hinges'}], 'utterance':'sentence number 2', 'speaker':'silver'}]]

Answer 1

试试这个：

my_list = [['id_1', {'frame':[{'door': 'window', 'closet':'pinches'}], 'utterance':'sentence number 1', 'speaker':'silver'}],
 ['id_2',{'frame':[{'door': 'window', 'closet':'pinches'},{'door': 'new_door', 'closet':'hinges'}], 'utterance':'sentence number 2', 'speaker':'silver'}],
 ['id_3', {'frame':[{'door': 'window', 'closet':'pins'}], 'utterance':'sentence number 3', 'speaker':'gold'}]]
new_list = []
new_list.extend([i for i in my_list if i[1]['speaker'] != "gold" ])

Answer 2

我认为你只需要“切换”2个内联循环：

removed =[item for item in my_list if not(item[1]['speaker'] == 'gold')]