处理错误请求的自定义错误消息

发布于 2025-01-17 12:42:12 字数 890 浏览 0 评论 0原文

我正在开发一个Android应用（客户端）。该服务器可与C＃一起使用。当我特别提出一些请求时，我会在不良请求上收到一条错误消息，例如“未找到HTTP/1.1 404”，当我搜索的项目不正确时，这是可以的。但是在不良要求下，服务器也向我发送了JSON中的消息主体，类似的事情是：

  {
    "responseMessage":"The item you searched not found"
  }

有没有办法获取此消息（而不是不好的请求消息'http/1.1 404找不到'）并将其显示为错误的请求？后端正常工作，我在邮递员身上检查一下。我的邮政请求守则是：

  Json := '{ '+
          ' "code":"'+str+'",'+
          ' "userid":'+userid+''+
          ' } ';
  JsonToSend := TStringStream.Create(Json, TEncoding.UTF8);
  try
   IdHTTP1.Request.ContentType := 'application/json';
   IdHTTP1.Request.CharSet := 'utf-8';

   try

   sResponse := IdHTTP1.Post('http://....', JsonToSend);

   except      
       on e  : Exception  do
        begin
             ShowMessage(e.Message); // this message is : HTTP/1.1 404 Not Found
             Exit;
        end;

   end;

  finally
  JsonToSend.Free;
  end;

原文

I'm developing an Android app (Client). The server works with C#. When I make some request specifically some Posts, I'm getting an error message on bad request such as 'HTTP/1.1 404 Not Found' which is okay when the item I searched for is incorrect. But on bad request the server sends me also a message body in JSON, something like this:

  {
    "responseMessage":"The item you searched not found"
  }

Is there a way to get this message (and NOT the bad request message 'HTTP/1.1 404 Not Found') and show it as a response of bad request? The back end works fine, I check it on Postman. My code of Post request is this:

  Json := '{ '+
          ' "code":"'+str+'",'+
          ' "userid":'+userid+''+
          ' } ';
  JsonToSend := TStringStream.Create(Json, TEncoding.UTF8);
  try
   IdHTTP1.Request.ContentType := 'application/json';
   IdHTTP1.Request.CharSet := 'utf-8';

   try

   sResponse := IdHTTP1.Post('http://....', JsonToSend);

   except      
       on e  : Exception  do
        begin
             ShowMessage(e.Message); // this message is : HTTP/1.1 404 Not Found
             Exit;
        end;

   end;

  finally
  JsonToSend.Free;
  end;

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一曲琵琶半遮面シ 2025-01-24 12:42:12

要接收错误时的 JSON 内容，您有 2 个选项：

捕获引发的 EIdHTTPProtocolException 并从其 ErrorMessage 属性读取 JSON，而不是 Message< /代码>属性：
<前><代码>尝试 sResponse := IdHTTP1.Post(...); 除了在 E: EIdHTTPProtocolException 上执行开始 sResponse := E.ErrorMessage; 结尾; on E: 例外开始 ShowMessage(e.Message); 出口; 结尾; 结尾;
启用 hoNoProtocolErrorException TIdHTTP.HTTPOptions 属性中的 code> 和 hoWantProtocolErrorContent 标志，以防止引发 TIdHTTP.Post() HTTP 失败时发生 EIdHTTPProtocolException，而只是将 JSON 返回到 sResponse 变量。如果需要，您可以使用 TIdHTTP.ResponseCode 属性来检测 HTTP 失败：
```
IdHTTP1.HTTPOptions := IdHTTP1.HTTPOptions + [hoNoProtocolErrorException, hoWantProtocolErrorContent];

尝试
  sResponse := IdHTTP1.Post(...);
  如果 IdHTTP1.ResponseCode <> 200然后...
除了      
  on E: 例外
    ...
结尾;
```

To receive the JSON content on errors, you have 2 options:

Catch the raised EIdHTTPProtocolException and read the JSON from its ErrorMessage property, not the Message property:

try
  sResponse := IdHTTP1.Post(...);
except      
  on E: EIdHTTPProtocolException do
  begin
    sResponse := E.ErrorMessage;
  end;
  on E: Exception do
  begin
    ShowMessage(e.Message);
    Exit;
  end;
end;

Enable the hoNoProtocolErrorException and hoWantProtocolErrorContent flags in the TIdHTTP.HTTPOptions property to prevent TIdHTTP.Post() from raising EIdHTTPProtocolException on HTTP failures, and instead just return the JSON to your sResponse variable. You can use the TIdHTTP.ResponseCode property to detect HTTP failures, if needed:
```
IdHTTP1.HTTPOptions := IdHTTP1.HTTPOptions + [hoNoProtocolErrorException, hoWantProtocolErrorContent];

try
  sResponse := IdHTTP1.Post(...);
  if IdHTTP1.ResponseCode <> 200 then ...
except      
  on E: Exception do
    ...
end;
```