使用字段值删除 firebase 文档

发布于 2025-01-17 11:21:17 字数 676 浏览 0 评论 0 原文

我正在尝试删除firebase文档，但问题是我想使用字段删除特定的文档。

如上所述，我在许多文档中都有USER_UID_1和USER_UID_2。我想在单击删除时将它们与（401和337）与（401和337）匹配。

    export const deleteChat = (chatId) => {
  return async (dispatch) => {
    const db = firestore();
    db.collection("conversations")
      .doc(chatId)
      .delete()
      .then(() => {
        dispatch({
          type: userConstants.GET_REALTIME_MESSAGES,
        });
      })
      .catch((error) => {
        console.log(error);
      });
  };
};

原文

I am trying to delete a firebase document but the problem is I want to delete specific documents using fields.

as seen above I have user_uid_1 and user_uid_2 in many documents. and I want to match them like every document with (401 and 337) should be deleted when I click delete.

    export const deleteChat = (chatId) => {
  return async (dispatch) => {
    const db = firestore();
    db.collection("conversations")
      .doc(chatId)
      .delete()
      .then(() => {
        dispatch({
          type: userConstants.GET_REALTIME_MESSAGES,
        });
      })
      .catch((error) => {
        console.log(error);
      });
  };
};

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睫毛溺水了 2025-01-24 11:21:17

您可以使用 where 方法进行查询，并为找到的每个文档循环使用 delete() 方法。请参阅下面的示例代码：

const coversations = db.collection('conversations')
.where('user_id_1', '==', '401')
.where('user_id_2', '==', '337');

coversations.get().then(function(querySnapshot) {
  querySnapshot.forEach(function(doc) {
    doc.ref.delete();
  });
});

如果 (401 和 337) 可以同时出现在 user_id_1 和 user_id_2 中，您可以执行一个简单的逻辑来检查是否存在场上发生的事情。请参阅下面的示例代码：

const coversations = db.collection('conversations');

coversations.get().then(function(querySnapshot) {
  querySnapshot.forEach(function(doc) {
    const n = ['401', '307'];
    if (n.includes(doc.data().user_uid_1) && n.includes(doc.data().user_uid_2)) {
      doc.ref.delete();
    }
  });
});

You could query using the where method and loop the delete() method for each document found. See sample code below:

const coversations = db.collection('conversations')
.where('user_id_1', '==', '401')
.where('user_id_2', '==', '337');

coversations.get().then(function(querySnapshot) {
  querySnapshot.forEach(function(doc) {
    doc.ref.delete();
  });
});

If (401 and 337) can be in both user_id_1 and user_id_2, you can do a simple logic to check if there's an occurrence on the field. See sample code below:

const coversations = db.collection('conversations');

coversations.get().then(function(querySnapshot) {
  querySnapshot.forEach(function(doc) {
    const n = ['401', '307'];
    if (n.includes(doc.data().user_uid_1) && n.includes(doc.data().user_uid_2)) {
      doc.ref.delete();
    }
  });
});

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