使用Python-Zeep向WSDL URL提出肥皂请求
我试图提出SOAP请求并遇到几个问题，我需要您的帮助来解决错误
from zeep import Client
client = Client(wsdl='http://<placeholder>/<serviceholder>.svc?wsdl')
response = client.service.MethodName(secret_code,secret_key,data.__str__())
并获得以下错误，
**zeep.exceptions.XMLSyntaxError: The XML returned by the server does not contain a valid {http://schemas.xmlsoap.org/soap/envelope/}Envelope root element. The root element found is HTML**
我需要2个输入，
methodName（secret_code，sertod_key，secret_key，
data .__ str.__ str.__ str.__ （））实际上需要data.tostring（）从c＃开始。我什至可以在Python中使用此__ str __吗？还是我应该使用其他东西？ （只要告诉我Python中的ToString（）等效方法- （只要
这确实意味着很多，因为我什至无法入睡或解决此错误。我很困惑！请
提前感谢
Im trying to make a SOAP request and running into a couple of issues and I would need your help in resolving the error
from zeep import Client
client = Client(wsdl='http://<placeholder>/<serviceholder>.svc?wsdl')
response = client.service.MethodName(secret_code,secret_key,data.__str__())
and getting the following error
**zeep.exceptions.XMLSyntaxError: The XML returned by the server does not contain a valid {http://schemas.xmlsoap.org/soap/envelope/}Envelope root element. The root element found is HTML**
I need 2 inputs,
The MethodName(secret_code,secret_key,
data.__str__()) actually needsdata.ToString()as that from c#. Am I even right to use this__str__in python or should I use something else?
( Just tell me the equivalent method of ToString() in pythonPlease tell me why Im getting that zeep.exception!
It would really mean a lot as I can't even sleep or resolve this error. Im so stuck! please help
Thanks in advance
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