开玩笑 - 具有对象为参数的模拟函数

Question

如何模拟一个具有对象作为参数并返回承诺的函数？

示例：

type FuncProps = {
  type: 'a' | 'b';
  isSelected: boolean;
  isDataIncluded: boolean;
};

type Props = {
  onDoSomething: ({ type, isSelected, isDataIncluded }: FuncProps) => Promise<void>;
};

当我这样做时，我会遇到错误：

const onDoSomethingMock = jest.fn(({ type: 'a', isSelected: true, isDataIncluded: false }) => Promise.resolve());

Answer 1

应该是：

type FuncProps = {
  type: 'a' | 'b';
  isSelected: boolean;
  isDataIncluded: boolean;
};

type Props = {
  onDoSomething: ({ type, isSelected, isDataIncluded }: FuncProps) => Promise<void>;
};

describe('71625454', () => {
  test('should pass', async () => {
    const onDoSomethingMock: Props['onDoSomething'] = jest.fn(({ type, isSelected, isDataIncluded }: FuncProps) =>
      Promise.resolve()
    );
    await onDoSomethingMock({ type: 'a', isSelected: true, isDataIncluded: false });
    expect(onDoSomethingMock).toBeCalled();
  });
});