Drupal 用户身份验证检查
我一直在尝试编写一个函数来检查用户是否经过身份验证，然后调用谷歌分析脚本来生成自定义报告。这是一个很大的麻烦，我相信 Drupal 并没有那么困难。有谁可以帮助或承担该项目吗？ 这应该是一件简单而直接的事情，但能够检查用户身份验证并不容易
我尝试使用 php 函数来检查用户是否登录，但我无法从中调用 javascript 函数。
我用 jquery 编写了一个脚本函数，在页面加载时调用脚本，但我无法检查用户是否使用 javascript 登录
I have been trying to write a function to check if user is authenticated and then call a google analytics script for custom report. This has been a big hassle and I believe Drupal is not that difficult. Is there anyone who can help or take up the project?
It should be a simple and straight forward thing to do but being able to check user authentication has not been easy
I've tried to use a php function to check if user is logged in but I was not able to call javascript function from it.
I wrote a script function with jquery calling the script on page load but I was not able to check if user is logged in using javascript
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也许这不是最好的选择，但是...
您如何看待从 JS 函数调用自定义模块的控制器，如果...则返回
true$currentUser = \Drupal::currentUser(); $uid = $currentUser->id(); 返回大于
0的数值，如果返回的值为0，则返回false代码>（匿名用户）？该控制器只需以 JSON 格式返回当前用户的 UID，然后可以从 JS 中读取。另一种尝试是在主题的 .theme 文件中编写 YOURTHEMENAME_preprocess_page() 函数来实现上述检查，并将值发送到模板，以便在某些 DOM 中的“数据属性”中呈现该值元素。渲染后，您可以从 JS 访问该值。
这些方法都不是做这些事情的“Drupal 方式”，但是......希望这些对您有所帮助。
干杯。
Maybe it's not the best option, but...
What do you think about calling, from your JS function, a custom module's controller, that return
trueif...$currentUser = \Drupal::currentUser(); $uid = $currentUser->id();returns a numeric value higher than0orfalseif the value returned is0(anonymous user)? This controller only should had to return the UID of the current user in a JSON format, readable afterwards from your JS.Another try would be to write a YOURTHEMENAME_preprocess_page() function in your theme's .theme file that implement the above check, and send the value to the template, in order to render the value in a 'data-attribute' in some DOM element. Once rendered, you could access the value from your JS.
None of these approachs are 'Drupal way' of doing the stuff, but... hope these help you.
Cheers.