重现“在 python 中创建具有点和线的 kml”问题邮政

Question

我正在尝试复制我在下面的链接中遇到的帖子，但出现了一条错误消息，我有点不确定如何解决： 链接到之前的帖子我'我尝试复制

我在以下行中收到错误：

coord = (row[5], row[6]) # lon, lat order

错误消息显示IndexError：字符串索引超出范围。我正在调用该列有我的纬度和经度的数字，即 5 & 6. 知道这个错误消息指的是什么吗？

这是我此时的脚本：

import geopandas as gpd
import simplekml
kml = simplekml.Kml()


inputfile = gpd.read_file("C:/Users/CombineKMLs_AddLabels/Data/ScopePoles.shp") 
points = []
for row in inputfile:
    coord = (row[5], row[6]) # lon, lat order
    pnt = kml.newpoint(name=row[2], coords=[coord])
    points.append(coord)    
    pnt.style.iconstyle.icon.href = 'http://maps.google.com/mapfiles/kml/shapes/placemark_square.png'

ls = kml.newlinestring(name='A LineString')
ls.coords = np.array(points)
ls.altitudemode = simplekml.AltitudeMode.relativetoground
ls.extrude = 1

kml.save("C:/Users/CombineKMLs_AddLabels/Data/PolesandLines.shp")

Answer 1

使用 df.iterrows() 迭代数据框，使用 df.loc[index, 'geometry'] 访问点。

import geopandas as gpd
import simplekml

kml = simplekml.Kml()

df = gpd.read_file("C:/Users/CombineKMLs_AddLabels/Data/ScopePoles.shp")

points = []
for index, poi in df.iterrows():
  pt = df.loc[index, 'geometry']
  coord = (pt.x, pt.y)
  pnt = kml.newpoint(name=index, coords=[coord])
  points.append(coord)
  pnt.style.iconstyle.icon.href = 'http://maps.google.com/mapfiles/kml/shapes/placemark_square.png'

ls = kml.newlinestring(name='A LineString', coords=points)

kml.save('PolesandLines.kml')