如何在 while 循环内每 x 秒运行一次代码？

发布于 2025-01-16 21:58:57 字数 439 浏览 0 评论 0原文

我的问题被简化了，我想根据数字 X 每 3 秒通过串口发送一个不同的信号到我连接的 Arduino 板，但是 X 的更新频率应该高于每三秒。我可以每 3 秒只更新 while 循环内的特定部分，而其他所有内容都正常吗？简而言之，这是我的 python 代码：

while something:

 x= aChangingValue

 if x > 130 and x < 300:
  print('d')
  arduino.write('d'.encode())
 if x < 130:
  print('r')
  arduino.write('r'.encode())
 if x > 300:
  print('l')
  arduino.write('l'.encode())

我尝试尝试系统时间和线程，但一无所获。有关相关主题的其他答案也对我不起作用。

原文

My problem simplified is that I want to send a different signal depending on the number X through serial to my connected Arduino board every 3 seconds however X should be updated more often than every three seconds.
Can I only update a specific part inside the while loop every 3 seconds and everything else normally?
Here is my python code in a nutshell:

while something:

 x= aChangingValue

 if x > 130 and x < 300:
  print('d')
  arduino.write('d'.encode())
 if x < 130:
  print('r')
  arduino.write('r'.encode())
 if x > 300:
  print('l')
  arduino.write('l'.encode())

I tried experimenting with the system time and threads but got nowhere. Other answers on relating topics also didn't work for me.

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烟火散人牵绊 2025-01-23 21:58:57

这将执行您所要求的操作。

import time

while something:

 x= aChangingValue

 if x > 130 and x < 300:
  print('d')
  arduino.write('d'.encode())
 if x < 130:
  print('r')
  arduino.write('r'.encode())
 if x > 300:
  print('l')
  arduino.write('l'.encode())
 time.sleep(3)

但请记住，这会阻塞该睡眠间隔。您的程序中没有发生任何其他事情，这可能工作得很好，但根据其他情况的发生，可能不会像您想象的那样工作。

This will do what you've asked.

import time

while something:

 x= aChangingValue

 if x > 130 and x < 300:
  print('d')
  arduino.write('d'.encode())
 if x < 130:
  print('r')
  arduino.write('r'.encode())
 if x > 300:
  print('l')
  arduino.write('l'.encode())
 time.sleep(3)

But remember that this is blocking for that sleep interval. Nothing else is happening in your program, which may work just fine, but depending on what else is happening, may not work how you imagine.

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