在 Mongo Java 中对数组进行多级排序
我有具有以下架构的文档,
id :
currencyCode : "USD"
businessDayStartDate : ""
hourZoneNumber : 1
customerCount : 0
itemQuantity : 4
nodeId : "STORE_DEV"
endpointId : "998"
amount : 4
我正在尝试查找与 nodeId 匹配的文档,并尝试聚合每个 hourZoneNumber 的 customerCount、itemQuantity 和金额。
下面是查询
db.getCollection("xxx").aggregate([
{ "$match": { "nodeId": { "$in":["STORE_DEV_1","STORE_DEV_2"] }, "businessDayStartDate" : { "$gte": "2022-03-04" , "$lte": "2022-03-07" } }},
{ "$group": {
"_id": {
"nodeId": "$nodeId",
"endpointId": "$endpointId",
"hourZoneNumber": "$hourZoneNumber"
},
"customerCount": { "$sum": "$customerCount" },
"itemQuantity" : { "$sum": "$itemQuantity" },
"amount" : { "$sum": "$amount" }
}
},
{ "$group": {
"_id": {
"nodeId": "$_id.nodeId",
"endpointId": "$_id.endpointId"
},
"hourZones": {
"$addToSet": {
"hourZoneNumber": "$_id.hourZoneNumber",
"customerCount": { "$sum": "$customerCount" },
"itemQuantity" : { "$sum": "$itemQuantity" },
"amount" : { "$sum": "$amount" }
}
}
}
},
{ "$group": {
"_id": "$_id.nodeId",
"endpoints": {
"$addToSet": {
"endpointId": "$_id.endpointId",
"hourZones": "$hourZones"
}
},
"total": {
"$addToSet": {
"customerCount": { "$sum": "$hourZones.customerCount" },
"itemQuantity" : { "$sum": "$hourZones.itemQuantity" },
"amount" : { "$sum": "$hourZones.amount" }
}
}
}
},
{
$project: {
_id: 0,
nodeId: "$_id",
endpoints: 1,
hourZones: 1,
total: 1
}
}
])
输出如下:
{
nodeId: 'STORE_DEV_2',
endpoints: [
{ endpointId: '998',
hourZones:
[
{ hourZoneNumber: 1,
customerCount: 0,
itemQuantity: 4,
amount: Decimal128("4") }
] } ],
total: [ { customerCount: 0, itemQuantity: 4, amount: Decimal128("4") } ],
}
{
nodeId: 'STORE_DEV_1',
endpoints:
[ { endpointId: '999',
hourZones:
[ { hourZoneNumber: 2,
customerCount: 2,
itemQuantity: 4,
amount: Decimal128("4") },
{ hourZoneNumber: 1,
customerCount: 4,
itemQuantity: 8,
amount: Decimal128("247.56") } ] } ],
total:
[ { customerCount: 6,
itemQuantity: 12,
amount: Decimal128("251.56") } ]
}
我希望输出排序为:首先按nodeId排序,然后按端点内的endpointId排序,最后按hourZones内的hourZoneNumber排序。
我该怎么做?我尝试对所有三个字段使用 sort() 。但它没有奏效。另外,有人可以确认是否有比上述代码更好的方法,因为我是 Mongo DB 的新手。
编辑: 请在 https://mongoplayground.net/p/FYm3QMMgrNI 查找示例输入数据
I have documents with below schema
id :
currencyCode : "USD"
businessDayStartDate : ""
hourZoneNumber : 1
customerCount : 0
itemQuantity : 4
nodeId : "STORE_DEV"
endpointId : "998"
amount : 4
I am trying to find documents that match nodeId and trying to aggregate customerCount, itemQuantity and amount for each hourZoneNumber.
Below is the query
db.getCollection("xxx").aggregate([
{ "$match": { "nodeId": { "$in":["STORE_DEV_1","STORE_DEV_2"] }, "businessDayStartDate" : { "$gte": "2022-03-04" , "$lte": "2022-03-07" } }},
{ "$group": {
"_id": {
"nodeId": "$nodeId",
"endpointId": "$endpointId",
"hourZoneNumber": "$hourZoneNumber"
},
"customerCount": { "$sum": "$customerCount" },
"itemQuantity" : { "$sum": "$itemQuantity" },
"amount" : { "$sum": "$amount" }
}
},
{ "$group": {
"_id": {
"nodeId": "$_id.nodeId",
"endpointId": "$_id.endpointId"
},
"hourZones": {
"$addToSet": {
"hourZoneNumber": "$_id.hourZoneNumber",
"customerCount": { "$sum": "$customerCount" },
"itemQuantity" : { "$sum": "$itemQuantity" },
"amount" : { "$sum": "$amount" }
}
}
}
},
{ "$group": {
"_id": "$_id.nodeId",
"endpoints": {
"$addToSet": {
"endpointId": "$_id.endpointId",
"hourZones": "$hourZones"
}
},
"total": {
"$addToSet": {
"customerCount": { "$sum": "$hourZones.customerCount" },
"itemQuantity" : { "$sum": "$hourZones.itemQuantity" },
"amount" : { "$sum": "$hourZones.amount" }
}
}
}
},
{
$project: {
_id: 0,
nodeId: "$_id",
endpoints: 1,
hourZones: 1,
total: 1
}
}
])
Output is as below:
{
nodeId: 'STORE_DEV_2',
endpoints: [
{ endpointId: '998',
hourZones:
[
{ hourZoneNumber: 1,
customerCount: 0,
itemQuantity: 4,
amount: Decimal128("4") }
] } ],
total: [ { customerCount: 0, itemQuantity: 4, amount: Decimal128("4") } ],
}
{
nodeId: 'STORE_DEV_1',
endpoints:
[ { endpointId: '999',
hourZones:
[ { hourZoneNumber: 2,
customerCount: 2,
itemQuantity: 4,
amount: Decimal128("4") },
{ hourZoneNumber: 1,
customerCount: 4,
itemQuantity: 8,
amount: Decimal128("247.56") } ] } ],
total:
[ { customerCount: 6,
itemQuantity: 12,
amount: Decimal128("251.56") } ]
}
I want the output to be sorted as : First sort by nodeId, then by endpointId within the endpoints and lastly by hourZoneNumber within hourZones.
How do I do this ? I tried using sort() with all the three fields. But it did not work. Also, can someone please confirm if there is any better way than the above code, as I am new to Mongo DB.
Edit:
Please find sample input data at https://mongoplayground.net/p/FYm3QMMgrNI
如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱,如果其他用户或者作者回复了您的评论,将不能在第一时间通知您!
发布评论
评论(1)
由于一开始就已经有了分离的数据,因此只需通过分组保存这些值,然后最后按它们排序即可。
编辑:为了对每个内部数组进行排序,我们在
$group
和$sort< 中使用
$push
而不是$addToSet
每个$group
之前的 /code>:您可以此处查看它
Since you already have the separated data at the beginning, it is simply a matter of saving these values through the grouping and then sorting by them in the end.
Edit: In order to sort each inner array, we use
$push
instead of$addToSet
inside the$group
and$sort
before each$group
:You can see it here