Python 不删除单词，但适用于单个字母

Question

我有一个项目，我应该使用下面的代码从语句中删除一些单词：

forbidden_words = ["And","is","to","from","the"]
f = "And thus brought us to this conclusion from the existing inference"

h = []
for i in f:
    if i not in forbidden_words:
        h.append(i)
"".join(h)

输出：'因此从现有的推论中得出了这个结论'

预期输出：'因此给我们带来了这个结论现有的推论'

我不知道为什么，但它适用于单个字母而不是单个单词，假设下面的代码：

forbidden_words = ["u","t","c","b","a"]
f = "And thus brought us to this conclusion from the existing inference"

h = []
for i in f:
    if i not in forbidden_words:
        h.append(i)
"".join(h)

输出：'and hs rogh so his onlsion from he exising推断'

为什么会发生这种情况？

Answer 1

您需要在空格上拆分 f 以便迭代单词：

h = []
for word in f.split():
    if word not in forbidden_words:
        h.append(word)
" ".join(h)

或者，使用生成器表达式：

" ".join(word for word in f.split() if word not in forbidden_words)

Answer 2

import re
forbidden_words = ["And","is","to","from","the"]
f = "And thus brought us to this conclusion from the existing inference"
for words in forbidden_words:
     f = ''.join(f.split(words))
f = re.sub(' +', ' ', f)

Answer 3

您必须迭代不在字符串上的字符串列表，如下所示。

forbidden_words = ["And","is","to","from","the"]
sentence = "And thus brought us to this conclusion from the existing inference".split()

filt_text = [ w  for w in sentence if w not in forbidden_words]

filt_sentence = ' '.join(filt_text)

print(filt_sentence )