如何在多字符串变量中的特定文本后使用正则表达式匹配随机数？

发布于 2025-01-16 15:11:45 字数 287 浏览 4 评论 0原文

在python中，我想通过在多字符串变量中搜索“Beginning Supply”来捕获一个随机数“100000000000000000”，如下所示，

import re

message = """Test
- 55244
Graph
- Tools
Beginning Supply
- 100000000000000000
Name
- Text2
Type"""

pattern = re.compile(r"Total.Supply...(\d+)")
pattern.match(message)

原文

In python, I want to capture a random number lets say '100000000000000000' by searching for 'Beginning Supply' in a multi string variable as shown below,

import re

message = """Test
- 55244
Graph
- Tools
Beginning Supply
- 100000000000000000
Name
- Text2
Type"""

pattern = re.compile(r"Total.Supply...(\d+)")
pattern.match(message)

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梦里梦着梦中梦 2025-01-23 15:11:45

默认情况下，. 不捕获\n 字符。为了实现这一点，您必须在模式中使用 DOTALL 标志。

如果你想使用 match：

import re

message = """Test
- 55244
Graph
- Tools
Beginning Supply
- 100000000000000000
Name
- Text2
Type"""

pattern = re.compile(r"(?:.*)(Beginning Supply...)(?P<num>\d+)(?:.*)", flags=re.DOTALL)
number = pattern.match(message).group("num")

如果你想使用 findall：

import re

message = """Test
- 55244
Graph
- Tools
Beginning Supply
- 100000000000000000
Name
- Text2
Type"""

pattern = re.compile(r"Beginning Supply...(\d+)", flags=re.DOTALL)
number = pattern.findall(message)[0]

注意：re.match 必须匹配整个字符串，否则它将返回无

By default, . does not capture \n characters. In order to achieve that you must use the DOTALL flag in your pattern.

If you want to use match:

import re

message = """Test
- 55244
Graph
- Tools
Beginning Supply
- 100000000000000000
Name
- Text2
Type"""

pattern = re.compile(r"(?:.*)(Beginning Supply...)(?P<num>\d+)(?:.*)", flags=re.DOTALL)
number = pattern.match(message).group("num")

If you want to use findall:

import re

message = """Test
- 55244
Graph
- Tools
Beginning Supply
- 100000000000000000
Name
- Text2
Type"""

pattern = re.compile(r"Beginning Supply...(\d+)", flags=re.DOTALL)
number = pattern.findall(message)[0]

NOTE: re.match must match the entire string or else it will return None

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