将坐标分配给没有坐标的 Xarray 数据集

发布于 2025-01-16 12:13:16 字数 785 浏览 3 评论 0原文

我有一个 netcdf，我想按坐标进行切片，但是当我打开它时，数据集似乎没有任何关联的坐标。它有尺寸和纬度/经度变量，但有任何坐标，所以它看起来像这样：

<xarray.Dataset>
Dimensions:             (y: 10980, x: 10980)
Dimensions without coordinates: y, x
Data variables: (12/20)
    lon                 (y, x) float32 ...
    lat                 (y, x) float32 ...

但我需要这样的东西：

<xarray.Dataset>
Dimensions:              (x: 7861, y: 7981)
Coordinates:
  * x                    (x) float64 1.992e+05 1.992e+05 ... 4.35e+05 4.35e+05
  * y                    (y) float64 4.586e+06 4.586e+06 ... 4.347e+06 4.347e+06
Data variables: (12/15)
    lon                  (y, x) float32 ...
    lat                  (y, x) float32 ...

我无法上传 netcdf 文件，因为它们非常重，对此感到抱歉。

任何了解如何做到这一点的人都将非常感激！

原文

I have a netcdf that I want to slice by coordinates, but when I open it, the dataset appears not to have any coordinates associated. It has dimmensions and lat/lon variables, but any coordinates, so it looks like this:

<xarray.Dataset>
Dimensions:             (y: 10980, x: 10980)
Dimensions without coordinates: y, x
Data variables: (12/20)
    lon                 (y, x) float32 ...
    lat                 (y, x) float32 ...

But I need something like this:

<xarray.Dataset>
Dimensions:              (x: 7861, y: 7981)
Coordinates:
  * x                    (x) float64 1.992e+05 1.992e+05 ... 4.35e+05 4.35e+05
  * y                    (y) float64 4.586e+06 4.586e+06 ... 4.347e+06 4.347e+06
Data variables: (12/15)
    lon                  (y, x) float32 ...
    lat                  (y, x) float32 ...

I cannot upload the netcdf files as they're extremely heavy, sorry about that.

Any grasp of how it can possibly be done would be very appreciated!!

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