如何防止障碍物和门重叠？

Question

# Imported Modules for Randomization and Turtle
import turtle as trtl
import random as rand
from random import *
# Painter Configuration and Screen Configuration
painter = trtl.Turtle()
distanceForward = 20
painter.pensize(5)
painter.speed(10000000)
painter.screen.setup(1000, 1000)


walls = 32


#This for loop is essential--> it creates 32 lines, and based on the conditions below, adds walls, barriers, and exits
for i in range(walls):
    #Register the beginning position of the Turtle.
    xBeginCor = painter.xcor()
    yBeginCor = painter.ycor()
    #Variables for randomization of Exits and Doors
    initialWallDistance = randint(1, distanceForward-5)
    doorDistance = randint(1,distanceForward-18)
    #Program for the Walls and their Randomization
    #Prevents the last 4 lines having barriers protruding
    #We feel this method of randomizing the wall distance was really innovative and that it works pretty well
    if i < walls - 4:
        painter.penup()
        painter.forward(initialWallDistance)
        painter.left(90)
        painter.pendown()
        painter.forward(30)
        painter.backward(30)
        painter.right(90)
        painter.penup()
        #Preventing overlapping for the Walls and Doors. This does not work perfectly, and sometimes the doors are too small as a result of this
        if doorDistance == range(0, 21):
          doorDistance + 20
          painter.forward(distanceForward - initialWallDistance)
        else:
          painter.forward(distanceForward - initialWallDistance)
    #Creates the randomization of the doors. This works really well, as it makes the turtle go a random distance forward from the beginning of the line, and create a door
    painter.goto(xBeginCor, yBeginCor)
    painter.pendown()
    painter.forward(doorDistance)
    painter.penup()
    painter.forward(20)
    painter.pendown()
    painter.forward(distanceForward-doorDistance)
    #Turn the turtle to create the next line 
    painter.right(90)
    #Change the length of the line so the next one is a longer distance
    distanceForward += 15
#Keeps window open
wn = trtl.Screen()
wn.mainloop()

我需要帮助阻止这些门和障碍物相互重叠。我还附上了一张图片来描述我的意思。

我正在编写此代码，以防止两者相互重叠：

        if doorDistance == range(0, 21):
          doorDistance + 20
          painter.forward(distanceForward - initialWallDistance)
        else:
          painter.forward(distanceForward - initialWallDistance)

没有任何效果。此时我完全困惑了，我不知道我在做什么。任何解释/帮助将不胜感激

注意：我是初学者，所以我无法使用任何复杂的技术

Answer 1

这段代码在Python方面不起作用：

if doorDistance == range(0, 21):
    doorDistance + 20

它应该是这样的：

if 0 <= doorDistance <= 20:
    doorDistance += 20

但这并不能解决你的问题。您避免门和障碍物重叠的逻辑不起作用。当你从中心螺旋上升时，你会设置指向下一层的障碍，并留下门缝。但当所有关于这些障碍所在位置的记忆都丢失时，重叠就会发生在下一个螺旋上。

我将你的代码重新修改为Python（仍然损坏）：

# Imported Modules for Randomization and Turtle
from turtle import Screen, Turtle
from random import randint

WALLS = 32

# Painter Configuration and Screen Configuration
screen = Screen()
screen.setup(1000, 1000)

painter = Turtle()
painter.hideturtle()
painter.pensize(5)
painter.speed('fastest')

distanceForward = 20

# This for loop is essential--> it creates 32 lines, and based on the conditions below, adds walls, barriers, and exits
for wall in range(WALLS):
    # Register the beginning position of the Turtle.
    beginCor = painter.position()

    # Variables for randomization of Exits and Doors
    initialWallDistance = randint(1, distanceForward-5)
    doorDistance = randint(1, distanceForward-18)

    # Program for the Walls and their Randomization
    # Prevents the last 4 lines having barriers protruding
    # We feel this method of randomizing the wall distance was really innovative and that it works pretty well

    if wall < WALLS - 4:
        painter.penup()
        painter.forward(initialWallDistance)
        painter.left(90)
        painter.pendown()
        painter.forward(30)
        painter.penup()
        painter.backward(30)
        painter.right(90)

        # Preventing overlapping for the Walls and Doors. This does not work perfectly, and sometimes the doors are too small as a result of this
        if 0 <= doorDistance <= 20:
            doorDistance += 20

        painter.forward(distanceForward - initialWallDistance)

    # Creates the randomization of the doors. This works really well, as it makes the turtle go a random distance forward from the beginning of the line, and create a door
    painter.goto(beginCor)
    painter.pendown()
    painter.forward(doorDistance)
    painter.penup()
    painter.forward(20)
    painter.pendown()
    painter.forward(distanceForward - doorDistance)

    # Turn the turtle to create the next line
    painter.right(90)

    # Change the length of the line so the next one is a longer distance
    distanceForward += 15

# Keeps window open
screen.mainloop()

你的逻辑似乎会产生无法解决的迷宫，就像你的示例一样。