使用 osmnx 绘制路线

Question

我正在尝试开发一个代码来使用 osnmx 在地图中绘制路线。这就是我所拥有的：

route=[292257954, 429200554, 1187086228, 1179868692, 430284828]
fig, ax = ox.plot.plot_graph_route(G_map, route, route_color='r', route_linewidth=4, route_alpha=0.5, orig_dest_size=100, ax=None)

在路由列表中，我将节点写为 OSM 的 ID。但我收到此错误：

    fig, ax = ox.plot.plot_graph_route(G_map, route, route_color='r', route_linewidth=4, route_alpha=0.5, orig_dest_size=100, ax=None)

  File ~\anaconda3\envs\ox\lib\site-packages\osmnx\plot.py:303 in plot_graph_route
    data = min(G.get_edge_data(u, v).values(), key=lambda d: d["length"])

AttributeError: 'NoneType' object has no attribute 'values'

有人可以帮助我吗？

Answer 1

• 通过在立交桥中查找OSMID来重建图，
• 显然这不是一条有效的路线，并且在重建图

[
  "No path between 292257954 and 429200554.",
  "No path between 429200554 and 1187086228.",
  "Either source 1187086228 or target 1179868692 is not in G",
  "Either source 1179868692 or target 430284828 is not in G"
]

完整代码后其中一个节点不存在

import requests
import pandas as pd
import shapely
import osmnx as ox
import networkx as nx
import json

route = [292257954, 429200554, 1187086228, 1179868692, 430284828]

# get lat/lon of osmids
df = pd.DataFrame(
    requests.get(
        f"http://overpass-api.de/api/interpreter?data=[out:json]; node(id:{','.join([str(n) for n in route])});out;"
    ).json()["elements"]
)

# get graph bound by nodes in list
poly = shapely.geometry.MultiPoint(df.loc[:, ["lon", "lat"]].values).convex_hull
G_map = ox.graph_from_polygon(poly, network_type="drive")

rr = []
err = []
for a,b in zip(route, route[1:]):
    try:
        r = nx.shortest_path(G_map, a, b, weight='length')
        rr.append(r)
    except nx.NetworkXNoPath as e:
        err.append(str(e))
    except nx.NodeNotFound as e:
        err.append(str(e))

print(json.dumps(err, indent=2))
        
if len(rr)>0:
    fig, ax = ox.plot.plot_graph_route(
        G_map,
        rr,
        route_color="r",
        route_linewidth=4,
        route_alpha=0.5,
        orig_dest_size=100,
        ax=None,
    )