根据模式“\r\n00”分割文件在科恩壳中

发布于 2025-01-16 00:14:32 字数 323 浏览 0 评论 0原文

我的文件 temp.txt 如下所示，

00ABC
PQR123400
00XYZ001234
012345
0012233

我想根据模式 '\r\n00' 拆分文件。在这种情况下，temp.txt 应拆分为 3 个文件，

first.txt: 
00ABC
PQR123400

second.txt
00XYZ001234
012345

third.txt
0012233

我尝试使用 csplit 来匹配模式 '\r\n00' 但调试显示无效模式。有人可以帮我使用 csplit 匹配确切的模式吗

原文

My file temp.txt looks like below

00ABC
PQR123400
00XYZ001234
012345
0012233

I want to split the file based on pattern '\r\n00'. In this case temp.txt should split into 3 files

first.txt: 
00ABC
PQR123400

second.txt
00XYZ001234
012345

third.txt
0012233

I am trying to use csplit to match pattern '\r\n00' but the debug shows me invalid pattern. Can someone please help me to match the exact pattern using csplit

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蝶…霜飞 2025-01-23 00:14:32

对于显示的示例，请尝试以下 awk 代码。用 GNU awk 编写和测试。

此代码将在您的系统中创建名称如下的文件：1.txt、2.txt 等。这还将负责关闭后端的输出文件，这样我们就不会出现臭名昭著的错误打开的文件太多。

awk -v RS='\r?\n00' -v count="1" '
{
  outputFile=(count++".txt")
  rt=RT
  sub(/\r?\n/,"",rt)
  if(!rt){
    sub(/\n+/,"")
    rt=prevRT
  }
  printf("%s%s\n",(count>2?rt:""),$0) > outputFile
  close(outputFile)
  prevRT=rt
}
'  Input_file

说明：为上述代码添加详细说明。

awk -v RS='\r?\n00' -v count="1" '      ##Starting awk program from here and setting RS as \r?\n00 aong with that setting count as 1 here.
{
  outputFile=(count++".txt")            ##Creating outputFile which has value of count(increases each time cursor comes here) followed by .txt here.
  rt=RT                                 ##Setting RT value to rt here.
  sub(/\r?\n/,"",rt)                    ##Substituting \r?\n with NULL in rt.
  if(!rt){                              ##If rt is NULL then do following.
    sub(/\n+/,"")                       ##Substituting new lines 1 or more with NULL.
    rt=prevRT                           ##Setting preRT to rt here.
  }
  printf("%s%s\n",(count>2?rt:""),$0) > outputFile   ##Printing rt and current line into outputFile.
  close(outputFile)                     ##Closing outputFile in backend.
  prevRT=rt                             ##Setting rt to prevRT here.
}
'  Input_file                           ##Mentioning Input_file name here.

With your shown samples, please try following awk code. Written and tested in GNU awk.

This code will create files with names like: 1.txt, 2.txt and so on in your system. This will also take care of closing output files in backend so that we don't get in-famous error too many files opened one.

awk -v RS='\r?\n00' -v count="1" '
{
  outputFile=(count++".txt")
  rt=RT
  sub(/\r?\n/,"",rt)
  if(!rt){
    sub(/\n+/,"")
    rt=prevRT
  }
  printf("%s%s\n",(count>2?rt:""),$0) > outputFile
  close(outputFile)
  prevRT=rt
}
'  Input_file

Explanation: Adding detailed explanation for above code.

awk -v RS='\r?\n00' -v count="1" '      ##Starting awk program from here and setting RS as \r?\n00 aong with that setting count as 1 here.
{
  outputFile=(count++".txt")            ##Creating outputFile which has value of count(increases each time cursor comes here) followed by .txt here.
  rt=RT                                 ##Setting RT value to rt here.
  sub(/\r?\n/,"",rt)                    ##Substituting \r?\n with NULL in rt.
  if(!rt){                              ##If rt is NULL then do following.
    sub(/\n+/,"")                       ##Substituting new lines 1 or more with NULL.
    rt=prevRT                           ##Setting preRT to rt here.
  }
  printf("%s%s\n",(count>2?rt:""),$0) > outputFile   ##Printing rt and current line into outputFile.
  close(outputFile)                     ##Closing outputFile in backend.
  prevRT=rt                             ##Setting rt to prevRT here.
}
'  Input_file                           ##Mentioning Input_file name here.

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