为什么用 pynput 无法检测到特定按键？

发布于 2025-01-15 13:26:56 字数 370 浏览 5 评论 0原文

我正在尝试制作一个在后台运行并检测按下某个键以创建一种热键的程序，但由于某种原因我无法检测到一个特定的键。

from pynput.keyboard import Key, Listener


def on_press(key):
    print(key)
    if str(key) == str('4'):
        print("test")

with Listener(on_press=on_press) as listener:
    listener.join()

预期产出：

'4'
test

实际产出：

'4'

原文

I'm trying to make a program which runs in the background and detects a certain key being pressed to create a kind of hotkey, but for some reason I can't detect one specific key.

from pynput.keyboard import Key, Listener


def on_press(key):
    print(key)
    if str(key) == str('4'):
        print("test")

with Listener(on_press=on_press) as listener:
    listener.join()

Expected Output:

'4'
test

Actual Output:

'4'

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习惯成性 2025-01-22 13:26:56

以下内容应该有所帮助：

from pynput.keyboard import Key, Listener
from pynput import keyboard


def on_press(key):
    print(key)
    #print(type(str(key)))
    if key.char == '4':
        print("test")

with Listener(on_press=on_press) as listener:
    listener.join()

输出如下：

'f'
'g'
'j'
'd'
'你'
'j'
'k'
'e'
'd'
'r'
't'
'j'
‘6’
‘6’
‘4’
测试
‘4’
测试
‘4’
测试
‘4’
测试
‘4’
测试

我使用了以下指南：

https://buildmedia.readthedocs。 org/media/pdf/pynput/latest/pynput.pdf

the following should help:

from pynput.keyboard import Key, Listener
from pynput import keyboard


def on_press(key):
    print(key)
    #print(type(str(key)))
    if key.char == '4':
        print("test")

with Listener(on_press=on_press) as listener:
    listener.join()

the output is following:

'f'
'g'
'j'
'd'
'y'
'j'
'k'
'e'
'd'
'r'
't'
'j'
'6'
'6'
'4'
test
'4'
test
'4'
test
'4'
test
'4'
test