graphQL 中的用户定义字段

发布于 2025-01-15 11:56:39 字数 1411 浏览 0 评论 0原文

使用石墨烯-Django 制作员工管理系统，我有一个 JsonB 字段，我不知道其形状，因为每个公司都会定义该形状。

这是模型：

    class Employee(models.Model):
        bonuses = models.JSONField(default=dict)
        #...OTHER FIELDS

这是类型：

    class EmployeeType(DjangoObjectType):
        class Meta:
            model = Employee
            fields = "__all__"

这是突变类：

    class EmployeeInfo(graphene.Mutation):

        employee = graphene.List(EmployeeType)

        class Arguments:
            bonuses = GenericScalar()
            #...OTHER FIELDS

        def mutate(self, info, **kwargs):
             #DOING STUFF
            return EmployeeInfo(employee=employee)

现在，假设一家公司想要向具有以下模式的开发人员提供奖金：

    export const EMPLOYEE_INFO = gql`
        mutation MutateEmployee(
                    $employeeOfTheMonth: Int
                    $mostPR: Int
                    $profitSharing: Int
        ) {
            employeeInfo(
                bonuses:{
                    employeeOfTheMonth: $employeeOfTheMonth
                    mostPR: $mostPR
                    profitSharing: $profitSharing
                }
                #...OTHER FIELDS
            ){....}
         }
     `

这是我当前的设置，问题是我在数据库中仅获得奖金的空值场地。请注意，我使用的是没有记录的 GenericScalar，我不知道这是否是错误的标量。

如果这是一家餐厅，显然奖金会有所不同，这就是为什么我需要这样的设置。

如何定义一个采用用户定义形状的字段？

原文

Making an employee management system with graphene-Django and I have a JsonB field that I don't know the shape of because each company will defined the shape.

Here's the model:

    class Employee(models.Model):
        bonuses = models.JSONField(default=dict)
        #...OTHER FIELDS

here's the type:

    class EmployeeType(DjangoObjectType):
        class Meta:
            model = Employee
            fields = "__all__"

Here's the mutation class:

    class EmployeeInfo(graphene.Mutation):

        employee = graphene.List(EmployeeType)

        class Arguments:
            bonuses = GenericScalar()
            #...OTHER FIELDS

        def mutate(self, info, **kwargs):
             #DOING STUFF
            return EmployeeInfo(employee=employee)

Now, say a company wants to give bonuses to a developer with the following schema:

    export const EMPLOYEE_INFO = gql`
        mutation MutateEmployee(
                    $employeeOfTheMonth: Int
                    $mostPR: Int
                    $profitSharing: Int
        ) {
            employeeInfo(
                bonuses:{
                    employeeOfTheMonth: $employeeOfTheMonth
                    mostPR: $mostPR
                    profitSharing: $profitSharing
                }
                #...OTHER FIELDS
            ){....}
         }
     `

This is my current setup, the problem is I get only null values in the database for the bonuses field. Notice that I'm using GenericScalar which is not documented and I don't know if that's the wrong scalar.

If this is a restaurant, obviously the bonuses will be different and that's why I need a setup like this.

How can I define a field that will take user defined shapes?

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止于盛夏 2025-01-22 11:56:39

我想这就是你需要的


    class EmployeeInfo(graphene.Mutation):

        employee = graphene.List(EmployeeType)

        class Arguments:
            bonuses = graphene.JSONString()
            #...OTHER FIELDS

I think this is what you need


    class EmployeeInfo(graphene.Mutation):

        employee = graphene.List(EmployeeType)

        class Arguments:
            bonuses = graphene.JSONString()
            #...OTHER FIELDS

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