将用户指定的日期添加到现有代码中

Question

我一直坚持能够将用户定义的日期添加到此 Days to Go 代码中。与嵌入的设定日期配合良好。但无法让它与输入线一起工作。

from datetime import datetime, time

b = input
event = (input('What is the name of your event?'))  # input the name of the event
year = int(input('Enter a year'))  # input the requires year
month = int(input('Enter a month'))  # input the required month
day = int(input('Enter a day'))  # input the required day

def date_diff_in_seconds(dt2, dt1):
    timedelta = dt2 - dt1
    return timedelta.days * 24 * 3600 + timedelta.seconds


def dhms_from_seconds(seconds):
    minutes, seconds = divmod(seconds, 60)
    hours, minutes = divmod(minutes, 60)
    days, hours = divmod(hours, 24)
    return (days, hours, minutes, seconds)


# Specified date
date1 = datetime.date(b[1], b[2], b[3])

# Current date
date2 = datetime.now()

print("\n%d days, %d hours, %d minutes, %d seconds" %
      dhms_from_seconds(date_diff_in_seconds(date2, date1)))
print()

Answer 1

首先，您错误地使用了b=input。这意味着您要使用函数名为 b 的 input 函数，例如 event = b('what is the name of your event?')。

相反，您可以在使用 input() 获取信息后将值分配给 b，例如 b = (event,year,month,day)。

并且您通过 from datetime import datetime 导入了 datetime 模块，您不需要明确地说 datetime.date，只需 date.但是，您可以在此处使用 datetime 而不是 date，如下所示：

from datetime import datetime, time

#b = input -> wrong usage
event = (input('What is the name of your event? '))  # input the name of the event
year = int(input('Enter a year '))  # input the requires year
month = int(input('Enter a month '))  # input the required month
day = int(input('Enter a day '))  # input the required day
b = (event, year, month, day) # you can assign date values to b

def date_diff_in_seconds(dt2, dt1):
    timedelta = dt2 - dt1
    return timedelta.days * 24 * 3600 + timedelta.seconds


def dhms_from_seconds(seconds):
    minutes, seconds = divmod(seconds, 60)
    hours, minutes = divmod(minutes, 60)
    days, hours = divmod(hours, 24)
    return (days, hours, minutes, seconds)


# Specified date
date1 = datetime(b[1], b[2], b[3]) # not datetime.date()

# Current date
date2 = datetime.now()

print("\n%d days, %d hours, %d minutes, %d seconds" %
      dhms_from_seconds(date_diff_in_seconds(date2, date1)))
print()

# if you want to print the event together:
print("\n%d days, %d hours, %d minutes, %d seconds left for %s" % (
            dhms_from_seconds(date_diff_in_seconds(date2, date1)) + (event,)))

结果如下：

What is the name of your event? birthday
Enter a year 2022
Enter a month 03
Enter a day 19

0 days, 14 hours, 40 minutes, 2 seconds
0 days, 14 hours, 40 minutes, 2 seconds left for Sunday # in case that you print the event together

Answer 2

我认为你的问题可能是这一行：

date1 = datetime.date(b[1],b[2],b[3])

尝试将其更改为：

date1 = datetime.date(year, month, day, 0, 0, 0)