为什么我的 Symfony 表单在从控制器渲染时不显示错误？

Question

我正在使用 EasyAdminBundle 并想为管理面板创建更改密码功能。一切正常，但有一个问题，当 RepeatedType 字段不相同且 oldPassword 不正确时，该表单不会显示错误。 错误已正确从 formType 发送到控制器，但树枝不显示它们。 ChangeAdminPasswordType

public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('oldPassword', PasswordType::class, [
                'constraints' => [
                    new NotBlank(),
                    new Length(['min' => 4])
                ],
            ])
            ->add('newPassword', RepeatedType::class, [
                'type' => PasswordType::class,
                'error_bubbling' => true,
                'invalid_message' => 'The password fields must match.',
                'first_options'  => ['label' => 'New Password'],
                'second_options' => ['label' => 'Repeat New Password'],

            ])
            ->add('save', SubmitType::class, [
                'attr' => ['class' => 'btn btn-primary'],
            ])
        ;
    }

ChangeAdminPasswordController

public function changeAdminPassword(Request $request): Response
    {
        $ex = new ChangeAdminPasswordDto();
        $form = $this->formFactory->create(ChangeAdminPasswordType::class, $ex);

        $view = $form->createView();

        $form->handleRequest($request);

        if ($form->isSubmitted() && $form->isValid()) {
            if (($this->changeAdminPassword)($this->getUser(), $form->getData())) {
                return $this->redirectToRoute('admin_dashboard');
            }
            $form->addError(new FormError('Current password is not correct'));
        }

        return $this->render('bundles/EasyAdminBundle/changeAdminPassword.html.twig', [
            'form' => $view,
        ]);
    }

changAdminPassword.html.twig

{% extends '@EasyAdmin/layout.html.twig' %}
{% block content_title %}
    <div class="content-header-title">
        <h1 class="title">
            Change password
        </h1>
    </div>

{% endblock %}

{% block main %}
    {{ form_errors(form) }}
    {{ form_start(form) }}
    <div class="col-md6 col-xxl-5">
        <div class="field-text form-group">
            {{ form_label(form.oldPassword) }}
            <div class="form-widget">
                {{ form_widget(form.oldPassword, { 'attr': {'class': 'form-control'}}) }}
            </div>
        </div>
        <div class="field-text form-group">
            {{ form_label(form.newPassword.first) }}
            <div class="form-widget">
                {{ form_widget(form.newPassword.first, { 'attr': {'class': 'form-control'}}) }}
            </div>
        </div>
        <div class="field-text form-group">
            {{ form_label(form.newPassword.second) }}
            <div class="form-widget">
                {{ form_widget(form.newPassword.second, { 'attr': {'class': 'form-control'}}) }}
            </div>
        </div>
    </div>
    <div class="page-actions">
        {{ form_row(form.save) }}
    </div>
    {{ form_end(form) }}
{% endblock %}

Answer 1

您将在提交之前创建表单视图 $view = $form->createView();。任何验证后都不会呈现任何错误消息...

更改此：

return $this->render('bundles/EasyAdminBundle/changeAdminPassword.html.twig', 
    [
        'form' => $view,
    ]);

为此：

return $this->render('bundles/EasyAdminBundle/changeAdminPassword.html.twig', 
    [
        'form' => $form->createView(),
    ]);