如何使用 a_timedelta.total_seconds() 创建一个在低于 0 时中断的倒计时器？

Question

import time,datetime
end_game = False
count=0
timer=10
date_and_time1 = datetime.datetime.now()
while True:
        if end_game == True:
          break
        choice3 = input("Break the clock.")
        
        if count == 4:
              print("YOU ARE OUT OF DEBT!")
              true = False
              break
        else:
              if choice3 == "break":
                date_and_time2 = datetime.datetime.now()
                a_timedelta = date_and_time2 - date_and_time1
                seconds = a_timedelta.total_seconds()
                if seconds <= 0:
                  print("You did not break the clock fast enough...")
                  time.sleep(2)
                  print("You lose.")
                  end_game = True
                elif seconds > 0:
                  count += 1
                  print(timer - seconds, " seconds left")
              else:
                print("The timer is running out. ('break')")

我对 python 很陌生。我正在尝试创建一个定时迷你游戏，作为较大程序的一部分，用户只需在 10 秒内输入“break”5 次即可获胜。目前，当计时器超时（秒<0）时，循环不会按其应有的方式中断。有没有简单的方法来解决这个问题？