函数的相反返回

发布于 2025-01-14 17:02:57 字数 489 浏览 1 评论 0原文

我正在做一些 Python 练习，由于某种原因，我的函数返回了相反的 bool 值。如果函数下的语句需要“不”才能正常工作 - 谁能解释我做错了什么？

number = int(input("Enter numbers you want to check: "))


def dividers(number):
temp_tab = range(2, number)
divider = 0

for x in temp_tab:
    while number % x == 0:
        divider += 1
        if divider > 1:
            return False
        else:
            return True


if not dividers(number):
   print("It is a prime number")
else:
   print("It is not a prime number")

原文

I am doing some Python exercisses and for some reason my fucntion is returning to me opposite bool value. If statement under the function need to has "not" to work properly - can anyone explain me what am I doing wrong?

number = int(input("Enter numbers you want to check: "))


def dividers(number):
temp_tab = range(2, number)
divider = 0

for x in temp_tab:
    while number % x == 0:
        divider += 1
        if divider > 1:
            return False
        else:
            return True


if not dividers(number):
   print("It is a prime number")
else:
   print("It is not a prime number")

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避讳 2025-01-21 17:02:57

看起来你想要一个函数来检查一个数字是否是素数：

def is_prime(number):
    if number <= 1: return False

    for x in range(2, number):
        if number % x == 0:
            return False
    return True


number = int(input("Enter numbers you want to check: "))

if is_prime(number):
    print("It is a prime number")
else:
    print("It is not a prime number")

It seems like you want a function to check if a number is prime:

def is_prime(number):
    if number <= 1: return False

    for x in range(2, number):
        if number % x == 0:
            return False
    return True


number = int(input("Enter numbers you want to check: "))

if is_prime(number):
    print("It is a prime number")
else:
    print("It is not a prime number")

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