使用 shell 命令比较两个文件，除了每行的第一个字节
我有两个日志文件，每一行都从时间开始。我想比较除了这个时间部分之外的文件。
例如：
file1.og
[20220201_133108] abc
[20220201_133108] defg
[20220201_133108] hi
[20220201_133108] jkl
file2.og
[20220202_172431] abc
[20220202_172431] defg
[20220202_172431] hi
[20220202_172431] jkl
它们是相同的，除了时间部分，所以想使用类似 diff [跳过第一个字节的选项] file1.log file2.log 会输出它们是相同的，有点像 cmp 的 -i 选项，但对于每一行
我不不知道该怎么做，我读过diff 和 cmp 的人，也许我错过了一些东西，但它似乎不是一个现有的选项？
另一方面，我不知道如何在比较之前使用某些 sed 或 awk 操作来修改文件，因为 diff 需要一个文件或目录，不是命令的输出？当然，除了创建临时文件，我希望这不是必需的
I have two log files with every line starting by the time. I'd like to compare the files except for this time part.
for exemple :
file1.og
[20220201_133108] abc
[20220201_133108] defg
[20220201_133108] hi
[20220201_133108] jkl
file2.og
[20220202_172431] abc
[20220202_172431] defg
[20220202_172431] hi
[20220202_172431] jkl
they are identical, except for the time part, so would like to use something like diff [option to skip first bytes] file1.log file2.log that would output that they are identical, a little bit like the -i option of cmp, but for each lines
I don't know how to do that, I've read the man of diff and cmp and maybe I missed something, but it doesn't seems like it's an existing option ?
In other hands, I don't see how I could use some sed or awk action to modify the file before comparing it, since diff is expecting a file, or a directory, not the output of a command ? Except of course to create temporary files, which I hope is not necessary
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如果您可以处理 Bash，则可以使用进程替换：
If you can handle Bash, you could use process substitution: