c#如何将long转换为单字节

发布于 2025-01-13 13:34:19 字数 543 浏览 0 评论 0原文

我正在尝试将 ac# 函数重写为 python。现在我看到这样一行：

timeArray[i - 1] = (byte)timestamp;

显然它只是解析 var“timestamp”，它是一个长度为 10 的长整型字节。但这是如何工作的，以及如何在 python 中重现它？作为参考，这里是 C# 代码的完整版本：

var timestamp = long.Parse("1647079653");
var timeArray = new byte[8];
timestamp /= 30L;
for (var i = 8; i > 0; i--)
{
    timeArray[i - 1] = (byte)timestamp;
    timestamp >>= 8;
}

这返回一个 [0,0,0,0,3,69,191,127] 的数组，

当我在 python 中执行此操作时（使用内置的字节函数），我得到了疯狂的数字数组的每个索引，尽管时间戳的初始值是正确的（如 6-7 位数字）有什么想法吗？

原文

Im trying to rewrite a c# function to python. Now ive come to a line which looks like this:

timeArray[i - 1] = (byte)timestamp;

Obviously it just parses the var "timestamp", which is a long of length 10 to a byte. But how does this work, and how can i reproduce it in python?
for reference, here the full version of the c# code:

var timestamp = long.Parse("1647079653");
var timeArray = new byte[8];
timestamp /= 30L;
for (var i = 8; i > 0; i--)
{
    timeArray[i - 1] = (byte)timestamp;
    timestamp >>= 8;
}

this returns an array of [0,0,0,0,3,69,191,127]

when i do it in python (using the built in bytes-function) i get insane numbers for each index of the array, altough the inital values of the timestamp are correct (like 6-7 digits)
Any ideas?

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橙幽之幻 2025-01-20 13:34:20

好吧，我想通了。它只取相应二进制的最后 8 位，这就是字节。工作的Python代码：

    for i in range(8,0,-1):
        num = str(bin(int(timestamp)))
        timeArray[i-1] = int(num[len(num)-8:],2)
        timestamp = int(timestamp)
        timestamp >>= 8

Okay i figured it out. It just takes the last 8 bits of the corresponding binary and this is then the byte. The working python code:

    for i in range(8,0,-1):
        num = str(bin(int(timestamp)))
        timeArray[i-1] = int(num[len(num)-8:],2)
        timestamp = int(timestamp)
        timestamp >>= 8

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