Flutter:LateError(LateInitializationError:字段“用户”尚未初始化。)

发布于 2025-01-13 13:23:14 字数 2089 浏览 2 评论 0原文

我不确定这个错误,因为用户应该在 Auth Provider 中初始化,然后我将能够在 User Provider 中使用它,但 flutter 继续给出这个错误。

这是我的代码。有人可以帮助解决或告诉我更好的形式来组织它吗?

AuthProvider

class AuthProvider extends ChangeNotifier {
  late final FirebaseAuth _auth;
  late final NavigationService _navigationService;
  late final DatabaseService _databaseService;

  late UserData user;
  AuthProvider() {
    _auth = FirebaseAuth.instance;
    _navigationService = GetIt.instance.get<NavigationService>();
    _databaseService = GetIt.instance<DatabaseService>();
    _auth.authStateChanges().listen((_user) {
      if (_user != null) {
        //_databaseService.updateUserLastSeenTime(_user.uid);
        _databaseService.getUser(_user.uid).then(
          (_snapshot) {
            if (_snapshot.exists) {
              if (_snapshot.data() != null) {
                user =
                    UserData.fromJson(jsonDecode(jsonEncode(_snapshot.data())));
                notifyListeners();
              }
            }
            _navigationService.removeAndNavigateToRoute('/home');
          },
        );
      } else {
        _navigationService.removeAndNavigateToRoute('/login');
      }
    });
  }

用户提供商

class UserProvider with ChangeNotifier {
  final DatabaseService _databaseService = DatabaseService();

  UserData _user = AuthProvider().user;
  UserData get getUser => _user;

  Future<void> refreshUser() async {
    UserData user = await _databaseService.getUserDetails();
    _user = user;
    notifyListeners();
  }

// update user name
  Future<void> editName(String name) async {
    try {
      await _databaseService.getUserDoc(_user.uid).update({'name': name});
    } catch (err) {
      print(err.toString());
    }
  }

// update user last name
  Future<void> editLastName(String lastName) async {
    try {
      await _databaseService
          .getUserDoc(_user.uid)
          .update({'lastName': lastName});
    } catch (err) {
      print(err.toString());
    }
  }
}

I am nit sure about this error because user should be inithialized in Auth Provider and then I will be able to use it in User Provider but flutter continue giving this error.

Here is my code. Can someone help to solve or tell me a better form to organize it?

AuthProvider

class AuthProvider extends ChangeNotifier {
  late final FirebaseAuth _auth;
  late final NavigationService _navigationService;
  late final DatabaseService _databaseService;

  late UserData user;
  AuthProvider() {
    _auth = FirebaseAuth.instance;
    _navigationService = GetIt.instance.get<NavigationService>();
    _databaseService = GetIt.instance<DatabaseService>();
    _auth.authStateChanges().listen((_user) {
      if (_user != null) {
        //_databaseService.updateUserLastSeenTime(_user.uid);
        _databaseService.getUser(_user.uid).then(
          (_snapshot) {
            if (_snapshot.exists) {
              if (_snapshot.data() != null) {
                user =
                    UserData.fromJson(jsonDecode(jsonEncode(_snapshot.data())));
                notifyListeners();
              }
            }
            _navigationService.removeAndNavigateToRoute('/home');
          },
        );
      } else {
        _navigationService.removeAndNavigateToRoute('/login');
      }
    });
  }

User Provider

class UserProvider with ChangeNotifier {
  final DatabaseService _databaseService = DatabaseService();

  UserData _user = AuthProvider().user;
  UserData get getUser => _user;

  Future<void> refreshUser() async {
    UserData user = await _databaseService.getUserDetails();
    _user = user;
    notifyListeners();
  }

// update user name
  Future<void> editName(String name) async {
    try {
      await _databaseService.getUserDoc(_user.uid).update({'name': name});
    } catch (err) {
      print(err.toString());
    }
  }

// update user last name
  Future<void> editLastName(String lastName) async {
    try {
      await _databaseService
          .getUserDoc(_user.uid)
          .update({'lastName': lastName});
    } catch (err) {
      print(err.toString());
    }
  }
}

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