使用 JSON 输出生成动态 html（使用 php）

发布于 2025-01-13 12:51:43 字数 736 浏览 0 评论 0原文

我有多个具有不同结构的 JSON 文件。我想要做的是用 HTML 自动显示这些 JSON 输出。

我的一些 JSON 输出如下：（将每个文件视为单独的文件，需要单独处理）

{
  "parts": [
    {
      "@attributes": {
        "id": "part1"
      },
      "car": "Peugeot",
      "service": 5,
      "location": 2996,
      "price": "44.95",
      "date": "2000-10-01"
    },
    
... other objects
  ]
}

{
   "licenses":[
      {
         "driver":"John",
         "year":26,
         "info":null
      },
      

... other objects
   ]
}

现在，为了处理这些文件，我在 PHP 上使用 GET 发送页面名称，并且我希望相应的 JSON 输出为使用 HTML 作为 $key 打印到屏幕上-> $value

如何使用 PHP 生成此动态 JSON 输出读取事件？我需要创建递归函数吗？

因为这些文件的结构彼此不同。我希望我能够解释我的问题。已经感谢您的帮助。

原文

I have multiple JSON files with different structures. What I want to do is to automatically display these JSON outputs with HTML.

Some of my JSON outputs are as follows: (Think of each of these as separate files and need to be processed separately)

{
  "parts": [
    {
      "@attributes": {
        "id": "part1"
      },
      "car": "Peugeot",
      "service": 5,
      "location": 2996,
      "price": "44.95",
      "date": "2000-10-01"
    },
    
... other objects
  ]
}

{
   "licenses":[
      {
         "driver":"John",
         "year":26,
         "info":null
      },
      

... other objects
   ]
}

Now, to process these files, I send the page name with GET on PHP and I want the corresponding JSON output to be printed to the screen with HTML as <span>$key</span> -> <span>$value</span>

How can I make this dynamic JSON output read event with PHP? Do I need to create a recursive function?

Because the files have different structures from each other. I hope I was able to explain my problem. Thanks already for yours help.

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风透绣罗衣 2025-01-20 12:51:43

我建议如下：

从 GET 或 POST 获取所需的 JSON 文件名，例如：
$jsonfilename = $_GET['文件'];

以上不包含任何安全保护！这是一个单独的主题，
所以做一些研究。

加载 json 文件并解析它：
$json = file_get_contents('/path/'.$jsonfilename);
$data = json_decode($json, true);
读取你的json数据：
foreach ($data as $key=>$value){
回显''.$key。' -> '.$值。'';
}

回复收藏 0 原文

策马西风 2025-01-20 12:51:43

您的 PARTS 文件的简单示例：

$json = '
{
    "parts":
    [
      {
        "@attributes": {
          "id": "part1"
        },
        "car": "Peugeot",
        "service": 5,
        "location": 2996,
        "price": "44.95",
        "date": "2000-10-01"
      },
      {
        "@attributes": {
          "id": "part2"
        },
        "car": "Renault",
        "service": 8,
        "location": 3100,
        "price": "99.95",
        "date": "2022-03-01"
      }
    ]
}';

$arr = json_decode($json, true);

foreach($arr["parts"] as $part) {
    foreach($part as $k => $v){
        if($k == "@attributes")
            echo "<h1>" . $v["id"] ."</h1>";
        else
            echo "<span>$k</span> -> <span>$v</span> <br/>";
    }
}

这将产生：

A simple example for your PARTS file:

$json = '
{
    "parts":
    [
      {
        "@attributes": {
          "id": "part1"
        },
        "car": "Peugeot",
        "service": 5,
        "location": 2996,
        "price": "44.95",
        "date": "2000-10-01"
      },
      {
        "@attributes": {
          "id": "part2"
        },
        "car": "Renault",
        "service": 8,
        "location": 3100,
        "price": "99.95",
        "date": "2022-03-01"
      }
    ]
}';

$arr = json_decode($json, true);

foreach($arr["parts"] as $part) {
    foreach($part as $k => $v){
        if($k == "@attributes")
            echo "<h1>" . $v["id"] ."</h1>";
        else
            echo "<span>$k</span> -> <span>$v</span> <br/>";
    }
}

This produces: