此外，return output; 需要为 return Output;，因为 C++ 区分大小写。
// overload operator<< to display array objects of any type T and size N
template<typename T, size_t N>
std::ostream &operator<<(std::ostream &Output, const std::array<T,N> &Arr) {
for (const auto &Element: Arr)
Output << Element << " ";
return Output;
}
The 2nd template argument of std::array is a size_t, not an int.
Also, return output; needs to be return Output; as C++ is case-sensitive.
// overload operator<< to display array objects of any type T and size N
template<typename T, size_t N>
std::ostream &operator<<(std::ostream &Output, const std::array<T,N> &Arr) {
for (const auto &Element: Arr)
Output << Element << " ";
return Output;
}
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std::array的第二个模板参数是size_t，而不是int。此外，
return output;需要为return Output;，因为 C++ 区分大小写。The 2nd template argument of
std::arrayis asize_t, not anint.Also,
return output;needs to bereturn Output;as C++ is case-sensitive.