如何使用 web3 py 从 BSC 交易收据的特定部分解码十六进制？

发布于 2025-01-12 19:55:03 字数 789 浏览 3 评论 0原文

我正在使用 web3 包编写 python 脚本。

流程说明：

我有一笔交易，我阅读了交易收据
txn_receipt = w3.eth.getTransactionReceipt('0x8ddd5ab8f53df7365a2feb8ee249ca2d317edcdcb6f40faae728a3cb946b4eb1')
仅在这个示例中，我读取了日志的特定部分。这将返回一个十六进制值。
x = txn_receipt['日志'][4]['数据']

问题：我如何解码这个十六进制？如果您进入 BSC SCAN，您将在块 453 处看到我期望的解码值。

预期值：

amount0In :
2369737542851785768252
amount1In :
0
amount0Out :
0
amount1Out :
82650726831815053455

请参见此处： https://bscscan.com/tx/0x8ddd5ab8f53df7365a2feb8ee249ca2d317edcdcb6f40faae728a3cb946b4eb1#eventlog

原文

I am writing a python script using web3 package.

The process explained:

I have a transaction, which I read the transaction receipt for
txn_receipt = w3.eth.getTransactionReceipt('0x8ddd5ab8f53df7365a2feb8ee249ca2d317edcdcb6f40faae728a3cb946b4eb1')
Just for this example, I read a specific section of the log. This returns a hex.
x = txn_receipt['logs'][4]['data']

PROBLEM:
How do I decode this hex? If you go to BSC SCAN, you will see the decoded value I am expecting at block 453.

Expected value:

amount0In :
2369737542851785768252
amount1In :
0
amount0Out :
0
amount1Out :
82650726831815053455

See here:
https://bscscan.com/tx/0x8ddd5ab8f53df7365a2feb8ee249ca2d317edcdcb6f40faae728a3cb946b4eb1#eventlog

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燃情 2025-01-19 19:55:03

假设您不需要键名称，您可以使用基本 python 来完成此操作（不需要 web3 库）。

BSC 日志中的数据字段是一串十六进制编码值，它只是十进制值的基数 16 表示。在您的示例中：

0x00000000000000000000000000000000000000000000008076b6fbd0ebb5bd3c000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000047b025e26b62ed08f

只需修剪开头，将其拆分，然后使用 python 的 int() 函数转换每个字符串：

hexdata = '0x00000000000000000000000000000000000000000000008076b6fbd0ebb5bd3c000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000047b025e26b62ed08f'

# Trim '0x' from beginning of string
hexdataTrimed = hexdata[2:]

# Split trimmed string every 64 characters
n = 64
dataSplit = [hexdataTrimed[i:i+n] for i in range(0, len(hexdataTrimed), n)]

# Fill new list with converted decimal values
data = []
for val in range(len(dataSplit)):
    toDec = int(dataSplit[val], 16)
    data.append(toDec)

print(data) 
# returns [2369737542851785768252, 0, 0, 82650726831815053455]

来源：

https://www.binaryhexconverter.com/hex-to-decimal-converter
https://www.w3schools.com/python/ref_func_int.asp

Assuming you don't need the key names, you could do this with basic python (no need for web3 library).

The data field in BSC logs is a string of hex encoded values, which is just a base 16 representation of the decimal value. In your example:

0x00000000000000000000000000000000000000000000008076b6fbd0ebb5bd3c000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000047b025e26b62ed08f

Just trim the beginning, split it up, and convert each string with python's int() function:

hexdata = '0x00000000000000000000000000000000000000000000008076b6fbd0ebb5bd3c000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000047b025e26b62ed08f'

# Trim '0x' from beginning of string
hexdataTrimed = hexdata[2:]

# Split trimmed string every 64 characters
n = 64
dataSplit = [hexdataTrimed[i:i+n] for i in range(0, len(hexdataTrimed), n)]

# Fill new list with converted decimal values
data = []
for val in range(len(dataSplit)):
    toDec = int(dataSplit[val], 16)
    data.append(toDec)

print(data) 
# returns [2369737542851785768252, 0, 0, 82650726831815053455]

Sources:

https://www.binaryhexconverter.com/hex-to-decimal-converter
https://www.w3schools.com/python/ref_func_int.asp

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