正确可视化俄罗斯地区

Question

我应该制作俄罗斯的具体地图，但我坚持了第一步：我无法正确地想象整个区域。为此，我使用该代码：

import geopandas as gpd
import matplotlib.pyplot as plt
path = 'C:\\Users\\sashk\\Python_projects\\Data_map_based\\data\\RUS_adm2.shp'
Map = gpd.read_file(path)
print(Map.shape)
Map.plot()
plt.show()

所以我得到：

请，如果有人知道如何修复它，请帮助

数据结构:

Answer 1

我找到了答案并且有效：

import matplotlib.pyplot as plt
import geopandas as gpd
from shapely.geometry import LineString
from shapely.ops import split
from shapely.affinity import translate
def shift_geom(shift, gdataframe, plotQ=False):
    shift -= 180
    moved_geom = []
    splitted_geom = []
    border = LineString([(shift,90),(shift,-90)])

    for row in gdataframe["geometry"]:
        splitted_geom.append(split(row, border))
    for element in splitted_geom:
        items = list(element)
        for item in items:
            minx, miny, maxx, maxy = item.bounds
            if minx >= shift:
                moved_geom.append(translate(item, xoff=-180-shift))
            else:
                moved_geom.append(translate(item, xoff=180-shift))

    # got `moved_geom` as the moved geometry            
    moved_geom_gdf = gpd.GeoDataFrame({"geometry": moved_geom})

    # can change crs here
    if plotQ:
        fig1, ax1 = plt.subplots(figsize=[8,6])
        moved_geom_gdf.plot(ax=ax1)
        plt.show()

    return moved_geom_gdf

path = 'C:\\Users\\sashk\\Python_projects\\Data_map_based\\data\\RUS_adm2.shp'
Map = gpd.read_file(path)

# shift geometry of Russia
new_rus = shift_geom(90, Map, False)
# restore the geometry to original geo-location
# ... geometry now in 1 piece
# ... option True --> make a plot
_ = shift_geom(-90, new_rus, True)