Mongo查询数据获取条件问题

发布于 2025-01-12 14:35:33 字数 1028 浏览 0 评论 0原文

示例输入

[{
    leadId : 20,
    status: in-progress,
    date: '07-03-2022',
    score:{
        create: 30,
        start: 45,
        in-progress: 90
    }
},
{
    leadId : 21,
    status: start,
    date: '06-03-2022',
    score:{
        create: 30,
        start: 45,
        in-progress: 90
    }
},
{
    leadId : 22,
    status: start,
    date: '05-03-2022',
    score:{
        create: 30,
        start: 45,
        in-progress: 78
    }
},
{
    leadId : 23,
    status: in-progress,
    date: '02-03-2022',
    score:{
        create: 30,
        start: 12,
        in-progress: 61
    }
}]

输出:

[{
    leadId : 20,
    status: in-progress,
    date: '07-03-2022',
    score:{
        create: 30,
        start: 45,
        in-progress: 90
    }
},
{
    leadId : 23,
    status: in-progress,
    date: '02-03-2022',
    score:{
        create: 30,
        start: 12,
        in-progress: 61
    }
}]

如果分数列中的当前状态值大于 60,我需要获取记录。

注意状态列值是动态更新的

Sample input

[{
    leadId : 20,
    status: in-progress,
    date: '07-03-2022',
    score:{
        create: 30,
        start: 45,
        in-progress: 90
    }
},
{
    leadId : 21,
    status: start,
    date: '06-03-2022',
    score:{
        create: 30,
        start: 45,
        in-progress: 90
    }
},
{
    leadId : 22,
    status: start,
    date: '05-03-2022',
    score:{
        create: 30,
        start: 45,
        in-progress: 78
    }
},
{
    leadId : 23,
    status: in-progress,
    date: '02-03-2022',
    score:{
        create: 30,
        start: 12,
        in-progress: 61
    }
}]

Output :

[{
    leadId : 20,
    status: in-progress,
    date: '07-03-2022',
    score:{
        create: 30,
        start: 45,
        in-progress: 90
    }
},
{
    leadId : 23,
    status: in-progress,
    date: '02-03-2022',
    score:{
        create: 30,
        start: 12,
        in-progress: 61
    }
}]

I need to fetch the records, if the current status value is greater than 60 within the score column.

Note status column value is dynamically updated

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评论(1

清风疏影 2025-01-19 14:35:33

这个问题不太清楚,但我想你需要这样的东西:

  db.collection.find({
       "score.in-progress": {
     $gt: 60
    },
      "status": "in-progress"
  })

afcoursecompoundindex on {score_in_progress:1,status:1} or {status:1,score_in_progress:1} is very likely be create

游乐场

Not very clear from the question , but I guess you need something like this:

  db.collection.find({
       "score.in-progress": {
     $gt: 60
    },
      "status": "in-progress"
  })

afcourse compound index on {score_in_progress:1,status:1} or {status:1,score_in_progress:1} is very likely to be created

playground

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