由逗号分隔的数字字符串列表的数据转换给我带来了多个错误，并且我无法获得正确的输出

Question

Section 1 Example A: Input of "1,2,3,4,5,6,7,8,9,10" should output 1 2 3 4 5 6 7 8 9 10
Section 1 Example B: Input of "1,2,6,4,8" should output 1 2 6 4 8

Section 2 Example C: Input of "1-3,5-9,12,14-15" should output 1 2 3 5 6 7 8 9 12 14 15
Section 2 Example D: Input of "2-4,3-7,10" should output 2 3 4 3 4 5 6 7 10

Section 3 Example E: Input of "3-1,5-9,12,14-15" should output 1 2 3 5 6 7 8 9 12 14 15
Section 3 Example F: Input of "2-4,7-3,10" should output 2 3 4 3 4 5 6 7 10

我尝试解决这个问题，但发现自己遇到了诸如 EOF 之类的错误，或者我将解决第 1 A 部分，但无法在循环中同时执行第 1 b 部分。他们应该是相互补充的。我不允许进行用户输入，所以我对如何解决这些问题感到非常困惑。

这是我现在的代码，它没有得到正确的输出并给我一个 EOF 错误。我应该采取哪些步骤来修复这些错误。

def PrintNumbers(s):
    a=s.split(',') #split() function returns a list where text between the character ',' becomes a list element
    i=0
    #It is said that negative numbers need not to be accounted so let's replace the negative numbers with 0.
    while i<len(a):
        c=a[i].count('-')
        if c==3: #it means that both the elements in the range are negative possible string representation will be of "-a--b" so we can remove the element from list
            a.remove(a[i])
            i=i-1
        elif c==2: #it means that one of the element is negative possible string will be either "-a-b" or "a--b" so we remo
            if a[i][0]=='-':#if the first element is'-' it means that the first number is negative(possible string is '-a-b') and second one is positive so lets change to first number to '0'
                a[i]=a[i][1:] #taking the whole remaining string and finding the position of next '-' and adding 0 before it
                pos=a[i].find('-')
                a[i]='0'+a[i][pos:]
            else:
                pos=a[i].find('-') #possible string will be of form "a--b" replace the whole value after first '-' with 0
                a[i]=a[i][0:pos+1]+'0'
        else: #it means that the list may be a range like "1-3" or a negative number "-1"
            if a[i][0]=='-': #if first character is negative number then we can change the whole string to '0'
                a.remove(a[i])
                i=i-1
        i+=1
                
    #It is said that ranges are also given so we need to split the list based on the seperator '-'
    for i in range(len(a)):
        a[i]=a[i].split('-') #We perform split operation to each array index and add the returned list to the same index.
    #If seperator character is not present in the string the whole string returns as a list element
    
    for i in range(len(a)):
        for j in range(len(a[i])):
            a[i][j]=a[i][j].strip() #strip() is used to remove white spaces at the starting and ending of the string if they are present
    
    m=-1 #m is used to find the maximum value given in the ranges it is initialized to -1
    
    for i in range(len(a)):
        for j in range(len(a[i])):
            if a[i][j].isdigit(): #check if the element is digit or not if digit convert it into integer
                a[i][j]=int(a[i][j])
            else:
                print('Error : Given string contains alphanumeric values ')
                return
            m=max(m,a[i][j]) #updating the value of m to maximum value 
            
    for i in range(len(a)):
        if len(a[i])==2: #if at an index the number of elements are 2 that means it represents range
            if a[i][0]>a[i][1]: #It is said that while representing range the ranges are represented backward so if the second element in range is less than the first element then we swap them 
                a[i][0],a[i][1]=a[i][1],a[i][0]
    #We are told to print the numbers 
    
    #Printing the numbers:
    for i in range(len(a)):
        if len(a[i])==1:
            print(a[i][0],end=' ')
        else:
            for j in range(a[i][0],a[i][1]+1): #printing all numbers in range
                print(j,end=' ')
    
s=input('Enter input : ')
PrintNumbers(s)

Answer 1

您可以使用正则表达式更好地处理 ab 案例

import re
def process_input(input: str)->None:
    to_print = []
    elements = input.split(',')
    for element in elements:
        try:
            num = int(element)
            to_print.append(element)
            continue
        except ValueError:
            pass
        numbers = [int(i) for i in re.match(r'(-?\d*)-(-?\d*)',element).group(1,2)]
        for x in range(min(numbers),max(numbers)):
            to_print.append(str(x))
    print(' '.join(to_print))
        
if __name__ == __main__:
    str_input = input('Enter input: ')
    process_input(str_input)