如何处理来自 PHPickerViewController 的视频和照片结果？

发布于 2025-01-12 02:51:39 字数 1203 浏览 0 评论 0原文

我需要用户能够从照片库中选择多张照片和视频。（使用 PHPickerViewController）我已经知道如何用这个获取图像：

func picker(_ picker: PHPickerViewController, didFinishPicking results: [PHPickerResult]) {
    var contentsData: [Data] = []
    for result in results {
        if result.itemProvider.canLoadObject(ofClass: UIImage.self) {
            result.itemProvider.loadObject(ofClass: UIImage.self) { selectedData, error in
                if let error = error {
                    print("PICKER ERROR: \(error)")
                } else {
                    if let selectedImage = selectedData as? UIImage {
                        if let selectedImageData = selectedImage.jpegData(compressionQuality: 0.5) {
                            contentsData.append(selectedImageData)
                            if contentsData.count == results.count {
                                self.parent.completion(contentsData)
                            }
                        }
                    }
                }
            }
        }
    }
    self.parent.presentationMode.wrappedValue.dismiss()
}

我假设我需要做的是检查 PHPickerResult 的每个结果是什么数据类型，然后相应地加载每个对象。问题是视频文件可能是 .mov、.mp4 等。如何将 PHPickerResult 识别为视频并进行相应处理？

原文

I need the ability for a user to select multiple photos and videos from there photo library. (Using PHPickerViewController) I already know how to get images with this:

func picker(_ picker: PHPickerViewController, didFinishPicking results: [PHPickerResult]) {
    var contentsData: [Data] = []
    for result in results {
        if result.itemProvider.canLoadObject(ofClass: UIImage.self) {
            result.itemProvider.loadObject(ofClass: UIImage.self) { selectedData, error in
                if let error = error {
                    print("PICKER ERROR: \(error)")
                } else {
                    if let selectedImage = selectedData as? UIImage {
                        if let selectedImageData = selectedImage.jpegData(compressionQuality: 0.5) {
                            contentsData.append(selectedImageData)
                            if contentsData.count == results.count {
                                self.parent.completion(contentsData)
                            }
                        }
                    }
                }
            }
        }
    }
    self.parent.presentationMode.wrappedValue.dismiss()
}

I would assume that what I would need to do is check what data type each result from PHPickerResult is and then load each object accordingly. The problem is that a video file could be .mov, .mp4, etc. How can I identify a PHPickerResult as a video and handle it accordingly?

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心碎的声音 2025-01-19 02:51:39

只需询问项目提供者是否有 UTType.movie.identifier 类型的项目即可。如果是这样，请继续通过调用 loadFileRepresentation(forTypeIdentifier: UTType.movie.identifier) 加载它。

实际代码：

    if prov.hasItemConformingToTypeIdentifier(UTType.movie.identifier) {
        self.dealWithVideo(result)
    } else if prov.canLoadObject(ofClass: PHLivePhoto.self) {
        self.dealWithLivePhoto(result)
    } else if prov.canLoadObject(ofClass: UIImage.self) {
        self.dealWithImage(result)
    }

Just ask whether the item provider has an item of type UTType.movie.identifier. If so, go ahead and load it by calling loadFileRepresentation(forTypeIdentifier: UTType.movie.identifier).

Actual code:

    if prov.hasItemConformingToTypeIdentifier(UTType.movie.identifier) {
        self.dealWithVideo(result)
    } else if prov.canLoadObject(ofClass: PHLivePhoto.self) {
        self.dealWithLivePhoto(result)
    } else if prov.canLoadObject(ofClass: UIImage.self) {
        self.dealWithImage(result)
    }

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