Python：使用变量/动态名称保存 JSON 响应？

发布于 2025-01-11 18:40:57 字数 508 浏览 0 评论 0原文

我对 Python 很陌生，我想知道如何在循环中保存 JSON 响应并根据 API 请求更改命名？

TestList = ["bitcoin", "avalanche", "ethereum"]

TestListLen = len(TestList)

for i in TestList:
    
# Request JSON response
    r = requests.get (f"https://api.coingecko.com/api/v3/coins/{i}/market_chart?vs_currency=usd&days=max&interval=daily")
    if r.status_code >= 201:
        continue
    data = r.json()

# How to save that response as eg. bitcoin.json or ethereum.json according to the names in TestList?

原文

i am pretty new to Python and I am wondering how I can save a JSON response in a loop and change naming according to API request?

TestList = ["bitcoin", "avalanche", "ethereum"]

TestListLen = len(TestList)

for i in TestList:
    
# Request JSON response
    r = requests.get (f"https://api.coingecko.com/api/v3/coins/{i}/market_chart?vs_currency=usd&days=max&interval=daily")
    if r.status_code >= 201:
        continue
    data = r.json()

# How to save that response as eg. bitcoin.json or ethereum.json according to the names in TestList?

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我不是你的备胎 2025-01-18 18:40:57

只需打开一个名为 {i}.json 的文件并将 json 结果转储到其中：

import requests
import json

TestList = ["bitcoin", "avalanche", "ethereum"]
for i in TestList:
    r = requests.get (f"https://api.coingecko.com/api/v3/coins/{i}/market_chart?vs_currency=usd&days=max&interval=daily")
    if r.status_code >= 201:
        continue
    data = r.json()
    with open(f'{i}.json', 'w') as fd:  #  add these two lines
        fd.write(json.dumps(data))

Just open a file with name {i}.json and dump the json result in it:

import requests
import json

TestList = ["bitcoin", "avalanche", "ethereum"]
for i in TestList:
    r = requests.get (f"https://api.coingecko.com/api/v3/coins/{i}/market_chart?vs_currency=usd&days=max&interval=daily")
    if r.status_code >= 201:
        continue
    data = r.json()
    with open(f'{i}.json', 'w') as fd:  #  add these two lines
        fd.write(json.dumps(data))

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