seq 创建列表季度 R

发布于 2025-01-11 18:24:49 字数 270 浏览 0 评论 0原文

我想使用两个季度之间所有季度的列表，将变量设置为字符。但我收到错误。

timeMin <- "2015Q1"
dissemPeriod <- "2022Q1"
list(seq(as.yearqtr(timeMin),as.yearqtr(dissemPeriod),by="quarter"))

Error in del/by : non-numeric argument to binary operator

原文

I want to use the list of all quarters between two quarters, set in variables as characters.
But I get an error.

timeMin <- "2015Q1"
dissemPeriod <- "2022Q1"
list(seq(as.yearqtr(timeMin),as.yearqtr(dissemPeriod),by="quarter"))

Error in del/by : non-numeric argument to binary operator

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深海夜未眠 2025-01-18 18:24:50

我不确定 seq 是否接受季度格式，因此您转换为日期格式并转换回季度：

library(zoo)
timeMin <- as.Date(as.yearqtr("2015Q1"))
dissemPeriod <- as.Date(as.yearqtr("2022Q1"))
as.yearqtr(seq(timeMin, dissemPeriod, by="quarter"))

# [1] "2015 Q1" "2015 Q2" "2015 Q3" "2015 Q4" "2016 Q1" "2016 Q2" "2016 Q3" "2016 Q4" "2017 Q1" "2017 Q2"
# [11] "2017 Q3" "2017 Q4" "2018 Q1" "2018 Q2" "2018 Q3" "2018 Q4" "2019 Q1" "2019 Q2" "2019 Q3" "2019 Q4"
# [21] "2020 Q1" "2020 Q2" "2020 Q3" "2020 Q4" "2021 Q1" "2021 Q2" "2021 Q3" "2021 Q4" "2022 Q1"

I'm not sure seq accepts quarter format, so you convert to date format and convert back to quarter:

library(zoo)
timeMin <- as.Date(as.yearqtr("2015Q1"))
dissemPeriod <- as.Date(as.yearqtr("2022Q1"))
as.yearqtr(seq(timeMin, dissemPeriod, by="quarter"))

# [1] "2015 Q1" "2015 Q2" "2015 Q3" "2015 Q4" "2016 Q1" "2016 Q2" "2016 Q3" "2016 Q4" "2017 Q1" "2017 Q2"
# [11] "2017 Q3" "2017 Q4" "2018 Q1" "2018 Q2" "2018 Q3" "2018 Q4" "2019 Q1" "2019 Q2" "2019 Q3" "2019 Q4"
# [21] "2020 Q1" "2020 Q2" "2020 Q3" "2020 Q4" "2021 Q1" "2021 Q2" "2021 Q3" "2021 Q4" "2022 Q1"

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