正则表达式捕获Python panda系列中的整个字符串
我有一个示例系列：
s = pd.Series(['Complexity Level 1', 'RandomName', 'I-Invoice Submission test', 'I-test2', 'I-string with multiple words'])
我试图仅捕获以“I-”开头的字符串。使用提取。
extract1 = s.str.extract(r'I-(\w+)')
当前输出：
0
0 NaN
1 NaN
2 Invoice
3 test2
4 string
当前仅提取第一个单词。但我想要标识符后面的所有单词和空格。最多可以有 5 个单词
这是正则表达式调整还是有更好的方法？
我想要的是：
0
0 NaN
1 NaN
2 Invoice Submission test
3 test2
4 string with multiple words
I have a sample series:
s = pd.Series(['Complexity Level 1', 'RandomName', 'I-Invoice Submission test', 'I-test2', 'I-string with multiple words'])
I'm trying to capture only strings that begin with "I-". Using extract.
extract1 = s.str.extract(r'I-(\w+)')
Current Output:
0
0 NaN
1 NaN
2 Invoice
3 test2
4 string
It's currently only extracting the first word. But I want all words and white space after the identifier. This could be up to 5 words
Is this a regex adjustment or is there a better method?
What I want is:
0
0 NaN
1 NaN
2 Invoice Submission test
3 test2
4 string with multiple words
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完成这项工作的正则表达式是
r'I-(.*)'?。含义：捕获"|-"之后的任何字符（直到换行符）。编辑（来自评论）：
要捕获逗号之前的任何字符，请使用
I-([^,]*)。含义：捕获"|-"之后除逗号 (,) 之外的任何字符。The regex that will do the job is
r'I-(.*)'?. Meaning: capture any character (until a newline) after"|-".EDIT (From comments):
To capture any character up until a comma use
I-([^,]*). Meaning: capture any character that is not a comma (,) after"|-".