检查内置字典 Swift 时游戏冻结

发布于 2025-01-11 14:45:31 字数 587 浏览 0 评论 0原文

我正在制作一个主要基于 SpriteKit 的简单文字游戏。有一个由 6 个字母组成的简单数组。当在我的 Spritekit 游戏中抓取一个字母并将其添加到数组中时，会通过一段简单的代码检查该数组现在是否是合法单词。

   let joined = wordArray.joined()
            print(joined)
            if UIReferenceLibraryViewController.dictionaryHasDefinition(forTerm: joined) {
                print("THATS A WORD")
                AudioServicesPlaySystemSound(systemSoundFanfare)
            }

这段代码位于我的 func didBegin(_ contact: SKPhysicsContact) 中) 函数

我的问题是，当执行此检查 0.5 秒左右时，整个游戏都会冻结。大概是因为它每次都会迭代整个字典！我怎样才能解决这个问题，以便在进行此检查时 Spritekit 场景不会被中断？

原文

I am making a simple word game based mostly in SpriteKit.
There is a simple array of 6 letters.
When a letter is grabbed in my Spritekit game and is added to the array a simple bit of code checks to see if the array is now a legitimate word..

   let joined = wordArray.joined()
            print(joined)
            if UIReferenceLibraryViewController.dictionaryHasDefinition(forTerm: joined) {
                print("THATS A WORD")
                AudioServicesPlaySystemSound(systemSoundFanfare)
            }

this bit of code is in my func didBegin(_ contact: SKPhysicsContact) function

My problem is the whole game freezes when it does this check for 0.5 seconds or so. Presumably because it is iterating though the entire dictionary each time!
How can I get around this so the Spritekit scene is not interrupted while this check happens?

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

月寒剑心 2025-01-18 14:45:31

使用一组来保存单词。 Swift 集合和 NSSet 有一个 contains 函数，您可以在其中提供字符串并返回该字符串是否在集合中。由于集合中的每个元素都是唯一的，因此在集合中查找项目比在数组中查找项目更快。

我在文字游戏中使用以下函数来快速检查字符串是否是单词

// words is a set containing the words
func isAWord(_ word: String) -> Bool {
    // The words set contains the empty string, but it's not a word.
    if word.isEmpty {
        return false
    }
    return words.contains(word)
}

Use a set to hold the words. Swift sets and NSSet have a contains function where you supply a string and returns whether the string is in the set. Because each element in a set is unique, finding an item in a set is faster than finding an item in an array.

I used the following function in a word game to quickly check if a string is a word

// words is a set containing the words
func isAWord(_ word: String) -> Bool {
    // The words set contains the empty string, but it's not a word.
    if word.isEmpty {
        return false
    }
    return words.contains(word)
}

回复收藏 0 原文

~没有更多了~