使用 XSLT,有没有办法使节点集的排序顺序与第二个节点集的顺序匹配?
我正在处理一组具有
区域的文档,该区域定义了原始数据类型组和其他结构的结构,以及
区域,它定义这些数据类型的实例的值。
原始 XML
<?xml version="1.0" encoding="utf-8" ?>
<Program>
<DataTypes>
<DataType Name="String20">
<Member Name="LEN" DataType="INTEGER" Dimension="0" />
<Member Name="DATA" DataType="BYTE" Dimension="20" />
</DataType>
<DataType Name="UDT_Params">
<Member Name="InAlarm" DataType="BIT" Dimension="0" />
<Member Name="SetPoint" DataType="FLOAT" Dimension="0" />
<Member Name="DwellTime" DataType="INTEGER" Dimension="0" />
<Member Name="UserName" DataType="String20" Dimension="0" />
</DataType>
</DataTypes>
<Tags>
<Tag Name="MyParameters" DataType="UDT_Params">
<Data Name="InAlarm" DataType="BIT" Value="0" />
<Data Name="SetPoint" DataType="FLOAT" Value="4.5" />
<Data Name="DwellTime" DataType="INTEGER" Value="10" />
<Data Name="UserName" DataType="String20">
<Data Name="LEN" DataType="INTEGER" Value="3" />
<Data Name="DATA" DataType="String20" > <!--The system I'm working in shows strings as arrays of BYTES in DataType, -->
Bob <!--but calls them out as Strings when they are used as tags. I cannot change it.-->
</Data>
</Data>
</Tag>
</Tags>
</Program>
样式表
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<!--Packing algorithm. Works fine on datatypes, but not on Tags.-->
<xsl:template name="pack-nodes">
<xsl:param name="nodes" />
<!--Omitted for brevity-->
</xsl:template>
<!--Pack DataTypes-->
<xsl:variable name="datatypes-packed">
<xsl:call-template name="pack-nodes">
<xsl:with-param name="nodes" select="/Program/DataTypes/DataType" />
</xsl:call-template>
</xsl:variable>
<!--Write DataTypes to output.-->
<xsl:template match="/Program/DataTypes">
<xsl:copy>
<xsl:for-each select="msxsl:node-set($datatypes-packed)">
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:copy>
</xsl:template>
<!--Pack tags-->
<xsl:variable name="tags-packed">
<xsl:call-template name="pack-nodes">
<xsl:with-param name="nodes" select="/Program/Tags/Tag" />
</xsl:call-template>
</xsl:variable>
<!--Write Tags to output.-->
<xsl:template match="/Program/Tags">
<xsl:copy>
<xsl:for-each select="msxsl:node-set($tags-packed)">
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
结果
<?xml version="1.0" encoding="utf-8"?>
<Program>
<DataTypes>
<DataType Name="String20">
<Member Name="LEN" DataType="INTEGER" Dimension="0"/>
<Member Name="DATA" DataType="BYTE" Dimension="20"/>
</DataType>
<DataType Name="Parameters" DataType="UDT_Params">
<Member Name="UserName" DataType="String20" Dimension="0"/>
<Member Name="SetPoint" DataType="FLOAT" Dimension="0"/>
<Member Name="DwellTime" DataType="INTEGER" Dimension="0"/>
<Member Name="InAlarm" DataType="BIT" Dimension="0"/>
</DataType>
</DataTypes>
<Tags>
<Tag Name="MyParameters" DataType="UDT_Params">
<Data Name="UserName" DataType="String20">
<Data Name="DATA" DataType="String20"> <!--Note that DATA comes before LEN -->
Bob
</Data>
<Data Name="LEN" DataType="INTEGER" Value="3"/>
</Data>
<Data Name="SetPoint" DataType="FLOAT" Value="4.5"/>
<Data Name="DwellTime" DataType="INTEGER" Value="10"/>
<Data Name="InAlarm" DataType="BIT" Value="0"/>
</Tag>
</Tags>
</Program>
我对 DataTypes 部分的操作添加了节点并更改了节点顺序。为了使该部分正常工作,标记元素必须与其各自数据类型的内容和顺序完全匹配。
如果我在 DataSet 节点的最终状态的内存中保留一个变量,是否有一种简单的方法可以让标记节点查找其数据集(通过 Structure 和 StructureMember @DataSet 属性,并相应地对它们的成员进行排序?
我有很难弄清楚从哪里开始。
注意:转换必须在 XSLT 1.0 中,我使用的是 .Net,并且不想引入大量对外部库的依赖。
I am acting on a set of documents that have a <DataTypes>
area, which defines the structure of groups of primative datatypes and other structures, and a <Tags>
area, which defines the values of instances of these datatypes.
Original XML
<?xml version="1.0" encoding="utf-8" ?>
<Program>
<DataTypes>
<DataType Name="String20">
<Member Name="LEN" DataType="INTEGER" Dimension="0" />
<Member Name="DATA" DataType="BYTE" Dimension="20" />
</DataType>
<DataType Name="UDT_Params">
<Member Name="InAlarm" DataType="BIT" Dimension="0" />
<Member Name="SetPoint" DataType="FLOAT" Dimension="0" />
<Member Name="DwellTime" DataType="INTEGER" Dimension="0" />
<Member Name="UserName" DataType="String20" Dimension="0" />
</DataType>
</DataTypes>
<Tags>
<Tag Name="MyParameters" DataType="UDT_Params">
<Data Name="InAlarm" DataType="BIT" Value="0" />
<Data Name="SetPoint" DataType="FLOAT" Value="4.5" />
<Data Name="DwellTime" DataType="INTEGER" Value="10" />
<Data Name="UserName" DataType="String20">
<Data Name="LEN" DataType="INTEGER" Value="3" />
<Data Name="DATA" DataType="String20" > <!--The system I'm working in shows strings as arrays of BYTES in DataType, -->
Bob <!--but calls them out as Strings when they are used as tags. I cannot change it.-->
</Data>
</Data>
</Tag>
</Tags>
</Program>
Stylesheet
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<!--Packing algorithm. Works fine on datatypes, but not on Tags.-->
<xsl:template name="pack-nodes">
<xsl:param name="nodes" />
<!--Omitted for brevity-->
</xsl:template>
<!--Pack DataTypes-->
<xsl:variable name="datatypes-packed">
<xsl:call-template name="pack-nodes">
<xsl:with-param name="nodes" select="/Program/DataTypes/DataType" />
</xsl:call-template>
</xsl:variable>
<!--Write DataTypes to output.-->
<xsl:template match="/Program/DataTypes">
<xsl:copy>
<xsl:for-each select="msxsl:node-set($datatypes-packed)">
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:copy>
</xsl:template>
<!--Pack tags-->
<xsl:variable name="tags-packed">
<xsl:call-template name="pack-nodes">
<xsl:with-param name="nodes" select="/Program/Tags/Tag" />
</xsl:call-template>
</xsl:variable>
<!--Write Tags to output.-->
<xsl:template match="/Program/Tags">
<xsl:copy>
<xsl:for-each select="msxsl:node-set($tags-packed)">
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Result
<?xml version="1.0" encoding="utf-8"?>
<Program>
<DataTypes>
<DataType Name="String20">
<Member Name="LEN" DataType="INTEGER" Dimension="0"/>
<Member Name="DATA" DataType="BYTE" Dimension="20"/>
</DataType>
<DataType Name="Parameters" DataType="UDT_Params">
<Member Name="UserName" DataType="String20" Dimension="0"/>
<Member Name="SetPoint" DataType="FLOAT" Dimension="0"/>
<Member Name="DwellTime" DataType="INTEGER" Dimension="0"/>
<Member Name="InAlarm" DataType="BIT" Dimension="0"/>
</DataType>
</DataTypes>
<Tags>
<Tag Name="MyParameters" DataType="UDT_Params">
<Data Name="UserName" DataType="String20">
<Data Name="DATA" DataType="String20"> <!--Note that DATA comes before LEN -->
Bob
</Data>
<Data Name="LEN" DataType="INTEGER" Value="3"/>
</Data>
<Data Name="SetPoint" DataType="FLOAT" Value="4.5"/>
<Data Name="DwellTime" DataType="INTEGER" Value="10"/>
<Data Name="InAlarm" DataType="BIT" Value="0"/>
</Tag>
</Tags>
</Program>
My operations on the DataTypes section adds nodes and changes the node order. For the section to work correctly, the tag elements must match the contents and order of their respective datatypes, exactly.
If I keep a variable in memory of the final state of the DataSet nodes, is there a simple way to have the tag nodes look up their dataset (via the Structure and StructureMember @DataSet attributes, and sort their members accordingly?
I'm having trouble figuring out where to start.
NOTE: Transformation must be in XSLT 1.0. I'm using .Net, and don't want to introduce a lot of dependencies on external libraries.
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在 XSLT 1.0 中这有点棘手(不是一切都如此吗?),但有时有效的技术是构造一个变量
$tokens
,其中包含按所需顺序的标记列表,例如“|Description|”。 Name|ProcessEntityIndex|Severity|...”,然后按select="string-length(substring-before($tokens, concat('|',@Name)))"
排序。It's a bit tricky in XSLT 1.0 (isn't everything?) but a technique that sometimes works is to construct a variable
$tokens
containing the list of tokens in the required order, for example "|Description|Name|ProcessEntityIndex|Severity|...", and then sort onselect="string-length(substring-before($tokens, concat('|',@Name)))"
.使用 Michael Kay 的排序建议,我最终得到以下结果:
样式表
Using Michael Kay's suggesting for sorting, I ended up with the following:
Stylesheet