避免在移动构造函数中移动成员样板？

Question

有时您仍然需要默认的移动构造函数行为（成员方式移动），但也希望修改移出的对象。以下面的场景为例，

class Base{...}; // some move-constructible class
class Member{...}; // also move constructible

class Derived : public Base
{
public:
    // does member-wise move, but nothing more
    // Derived(Derived &&) = default;

    // does member-wise move, same as default
    // and also modifies `other`
    Derived(Derived && other)
        : a(std::move(other.a))
        , b(std::move(other.b))
        , ... // the rest of members
    {
        other.put_into_invalid_state_or_something();
    }

    //...............................................
    //      More functions
    //...............................................

private:
    // a lot of members...
    Member a,b,c,d,e,f,g,h,i;
};

这可能是一个愚蠢的问题，但是有没有办法避免为每个成员都编写动作呢？