如果字符串包含文本，如何创建

Question

如果字符串包含正在读取的文件，如何创建？

• 我的index.js

if (command == "creategame") {
const lang = args[0]
const gameTypes = args[1]
const allLang = fs.readFileSync('language-supported.txt', 'utf-8')

if(!lang) {
    message.reply("Need language.\nExample: !creategame en character\n\n!creategame <language> <gameType> (ANIMALS/CHARACTER)")
} else {
    fs.readFile('./language-supported.txt', function (err, data) {
        if (err) throw err;

// here ima try if the stringMessage includes a text in language-supported.txt
        if(lang.includes(data)) {

            if(!gameTypes) {
                message.reply("Need game types.\nExample: !creategame en character\n\n!creategame <language> <gameType> (ANIMALS/CHARACTER)")
            } else {
                if(gameTypes == "animals" || gameTypes == "character") {
                if(fs.existsSync(gamePath)) {
                    const { language, gameTypes } = require(gamePath);
                    message.reply(`You already create a game, Type: ${gameTypes}, Language: ${language}`)
                } else {
                const conntent = `{ "languageGame": "${lang}", "gameTypes": "${gameTypes}" }`;
                message.reply("game created!")
                fs.writeFileSync(gamePath, conntent);
                }
                } else {
                    message.reply(`The bots only support gametype: **ANIMALS/CHARACTER** not a ${gameTypes}`)
                }
            }   
        } else {
            message.reply("wait i think thats not a Language.")
        }
      });
   
}
}

• 我的语言支持.txt

af
am
ar
az
be
bg
bn
bs
ca
ceb
co
cs
cy
da
de
el
en
eo

• 当我运行代码时，它总是显示等等我认为这不是一种语言。
• 怎么办如果字符串/文本包含在列表language-supported.txt中，我会做什么？

Answer 1

我认为有 1 个小缺失。

if(lang.includes(data)) {

应该是

if(data.includes(lang)) {