我如何指定先前表格的对象?
在我的项目中,我想使用由先前表单创建的对象:
这是我的数据库的架构:
My QuizController
public function creation(Request $request){
$quiz = new Quiz();
$user = $this->getUser();
$formQuiz = $this->createForm(QuizType::class, $quiz);
$formQuiz->handleRequest($request);
if ($formQuiz->isSubmitted() && $formQuiz->isValid() ) {
$quiz->setCreatedAt(new DateTimeImmutable());
$quiz->setCreatedBy($user);
$entityManager = $this->getDoctrine()->getManager();
$entityManager->persist($quiz);
$entityManager->flush();
return $this->redirectToRoute('creation_questions');
}
return $this->render('quiz/creation.html.twig', [
'formQuiz' => $formQuiz->createView(),
]);
}
和我的 QuestionController 必须与测验表单连接
public function creation_questions(Request $request){
$quiz = ?
$question = new Questions();
$formQuestions = $this->createForm(QuestionType::class, $question);
$formQuestions->handleRequest($request);
if ($formQuestions->isSubmitted() && $formQuestions->isValid() ) {
$question->setCreatedAt(new DateTimeImmutable());
$question->setQuiz($quiz);
$entityManager = $this->getDoctrine()->getManager();
$entityManager->persist($question);
$entityManager->flush();
return $this->redirectToRoute('home');
}
return $this->render('questions/questions.html.twig', [
'formQuestion' => $formQuestions->createView()
]);
}
我必须写什么来代替“?”?
In my project I want to use the object created by my precedent form:
Here is the schema of my database:
My QuizController
public function creation(Request $request){
$quiz = new Quiz();
$user = $this->getUser();
$formQuiz = $this->createForm(QuizType::class, $quiz);
$formQuiz->handleRequest($request);
if ($formQuiz->isSubmitted() && $formQuiz->isValid() ) {
$quiz->setCreatedAt(new DateTimeImmutable());
$quiz->setCreatedBy($user);
$entityManager = $this->getDoctrine()->getManager();
$entityManager->persist($quiz);
$entityManager->flush();
return $this->redirectToRoute('creation_questions');
}
return $this->render('quiz/creation.html.twig', [
'formQuiz' => $formQuiz->createView(),
]);
}
And my QuestionController that must be connected with the quiz form
public function creation_questions(Request $request){
$quiz = ?
$question = new Questions();
$formQuestions = $this->createForm(QuestionType::class, $question);
$formQuestions->handleRequest($request);
if ($formQuestions->isSubmitted() && $formQuestions->isValid() ) {
$question->setCreatedAt(new DateTimeImmutable());
$question->setQuiz($quiz);
$entityManager = $this->getDoctrine()->getManager();
$entityManager->persist($question);
$entityManager->flush();
return $this->redirectToRoute('home');
}
return $this->render('questions/questions.html.twig', [
'formQuestion' => $formQuestions->createView()
]);
}
What do I have to write in place of the '?'?
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您不显示您的路由,但您可以使用 SensioFrameworkExtraBundle 中的 paramConverte“magic” 并执行类似的操作。
其中
/someRoute/{id}
的{id}
部分是测验 ID。 Symfony 应该自动获取与该 id 匹配的测验。或者您可以更明确地说明参数转换器应如何解释此类值。更多信息请点击这里 https://symfony.com/bundles/SensioFrameworkExtraBundle/current/annotations /converters.html或者,您可以传递测验 ID 并手动获取测验(不太神奇,但完全合法)。
You don't show your routing but you could use paramConverte "magic" from SensioFrameworkExtraBundle and do something like this.
Where the
{id}
part of/someRoute/{id}
is the Quiz Id. Symfony should automagically fetch the Quiz matching that id. Or you can be more explicit about how the param converter should interpret such a value. More info here https://symfony.com/bundles/SensioFrameworkExtraBundle/current/annotations/converters.htmlAlternatively, you could pass the quiz id and fetch the quiz manually (less magic but totally legit).